Particle has position vector 2i + j

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Discussion Overview

The discussion revolves around a particle's motion described by its position vector and velocity. Participants explore the calculation of the particle's position vector after a certain time and the distance traveled, focusing on the relationship between velocity and direction.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • A particle has an initial position vector of 2i + j and is moving with a speed of 10 m/s in the direction of 3i - 4j.
  • One participant notes that the velocity vector must be parallel to 3i - 4j and questions the implications for its form.
  • Another participant clarifies that the velocity vector is the time-derivative of the position vector and suggests a proportionality factor k for the velocity vector.
  • A participant calculates the value of k as 2 based on the given speed.
  • Displacement is stated as 20i - 23j by one participant, which is later confirmed by another participant.

Areas of Agreement / Disagreement

Participants generally agree on the calculations related to the velocity vector and displacement, but there is some initial confusion regarding the distinction between the velocity vector and its direction.

Contextual Notes

There are unresolved aspects regarding the derivation of the position vector at t=3 seconds and the assumptions made about the direction and magnitude of the velocity vector.

Gughanath
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A particle has position vector 2i + j (i is along x-axis and j is along y axis) initially. and is moving with speed of 10m/s in the direction 3i-4j. Find its position vector when t=3 and the distance it has travlled in those 3 seconds.
Please help me with the first part of the question. :confused:
 
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Your velocity vector must satisfy two conditions:
1. It must be parallell to 3i-4j
What does that tell you about the form of the velocity vector?
2. The velocity vector's magnitude is 10.
 
it says the particle is traveling in the direction 3i-4j, isn't that the velocity vector??
 
Gughanath said:
it says the particle is traveling in the direction 3i-4j, isn't that the velocity vector??
Nope: the velocity vector is the time-derivative of the position vector.
What you've been given is that the velocity vector is PARALLELL to (in the direction of) 3i-4j, that is:
[tex]\vec{v}=k(3\vec{i}-4\vec{j})[/tex]
where k>0 is a proportionality factor (unknown at the moment!).
In addition, you have been given that the SPEED is 10, that is:
[tex]||\vec{v}||=10[/tex]
Use the last equation to determine k.
 
phew...you just saved me from a headache. Now I get it. My value for k is 2.
 
displacement is 20i -23j
 
Gughanath said:
displacement is 20i -23j
Yes, that's right.
 

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