Calculate Tension R of Mass m on String of Length l at Temp T

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Homework Help Overview

The problem involves calculating the tension in a string of length l, which has a mass m fixed at its midpoint and rotates about an axis at its ends, while also considering the effect of temperature T on the system. The discussion centers around the relationship between tension, distance x between the ends of the string, and thermal energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the components of tension and their relation to centripetal force, the energy of the rotating mass, and the implications of thermal equilibrium. Questions arise about the validity of equating macroscopic energy with thermal energy and the role of the string's mass.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the energy relationships involved. Some guidance has been offered regarding the relationship between distance and rotational radius, but there is no consensus on the appropriateness of equating macroscopic and thermal energies.

Contextual Notes

There are questions about the assumptions made regarding the mass of the string and the potential effects of temperature on its length, indicating a need for clarification on these points.

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A weight of mass m is fixed to the middle point of a string of length l and rotates about an axis joining the ends of the string. The system is in contact with its environment at temperature T. Calculate the tension R between the ends of the string in terms of its dependence upon distance x between the ends and the temperature.

My thoughts:

clearly, the x-components of the tension will cancel and we are left with the y-components of the tension which provides the centripetal force.

The energy of the rotating mass is given by 1/2 I w^2 (where w is the angular frequency). Since the string is in thermal equilibrium with the envrionment we can equate it with the average thermal energy for 1 degree of freedom: 1/2 kT

What I don't understand, is how to go from the energy to the tension on the string.
 
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Well you know the energy of the string plus the mass. Since the string is assumed to be massless(right?) then you know the velocity as mass rotates.

The distance between the two ends of the string X will decide the radius at which the mass rotates.

Does this help?
 
I'm very sure u can't equate anything macroscopic with [itex]\frac{1}{2} kT[/itex]

Daniel.
 
Is there a way to solve the problem if it is macroscopic?
 
dextercioby said:
I'm very sure u can't equate anything macroscopic with [itex]\frac{1}{2} kT[/itex]

Daniel.

even if you did, if a macroscopic energy system had kT worth of energy, ie. 0.026 eV at room temperature, it'd be basically zero relative to the moment of inertia of the mass.

is there a coefficient of thermal expansion for the string or something like that, which would affect the length of the string as a function of temperature?
 

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