Find Head of Vector [a,b,c] with Length 3 in Same Direction as [−3,−4,12]

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SUMMARY

The discussion focuses on finding the head of a vector [a,b,c] with a length of 3 that is in the same direction as the vector a = [-3,-4,12]. The user correctly identifies the magnitude of vector a as 13 and establishes the relationships between the components of the vectors using cosine angles. However, discrepancies arise when comparing their calculated values for a, b, and c with those provided in a reference book. The user seeks clarification on their method and the correct values.

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PiRsq
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The question asked me to find the head of a vector [a,b,c] whose length is 3 and is in the same direction as vector
a=[-3,-4,12]

So I found the follwing:

Let vector x be the unknown vector

|a|=13
|x|=3

Since they are both in the same direction, they both must have the same direction angles right?

So:

Cos alpha = -3/13 which is equal to a/3
Cos beta = -4/13 which is equal to b/3
Cos gamma = 12/13 which is equal to c/3

Then I got the values for a,b and c but the book shows me a different answer. What am I doing wrong here?
 
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What values did you get, and what does the book say?
 
I found my answer to be correct because I did a similar question and found my method to work. Thx though
 

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