Solving the Train and Spring Problem

  • Thread starter Thread starter whereisccguys
  • Start date Start date
  • Tags Tags
    Spring Train
Click For Summary
SUMMARY

The discussion centers on calculating the maximum speed of a train that can be stopped by a spring with a compression of 4.2 feet. The key parameters include a maximum stopping acceleration of g/2 and an assumed train mass of 0.5 million kilograms. The initial approach using kinetic energy equated to work done by the spring was incorrect; instead, the correct method involves using Hooke's Law to find the spring constant and the appropriate spring energy formula. The final calculated maximum speed of the train is 2.5 m/s.

PREREQUISITES
  • Understanding of Hooke's Law and spring mechanics
  • Basic principles of kinetic energy and work-energy theorem
  • Familiarity with gravitational acceleration (g) and its applications
  • Knowledge of unit conversions (feet to meters)
NEXT STEPS
  • Study the derivation of spring constant using Hooke's Law
  • Learn about energy conservation in mechanical systems
  • Explore the implications of maximum deceleration in safety engineering
  • Investigate real-world applications of spring systems in transportation safety
USEFUL FOR

Engineers, physicists, and safety analysts involved in transportation systems, particularly those focused on train safety mechanisms and energy absorption technologies.

whereisccguys
Messages
21
Reaction score
0
train and spring problem

problem: At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety device to stop the train so that it will not go plowing through the station if the engineer misjudges the stopping distance. While waiting, you wonder what would be the fastest train that the spring could stop by being fully compressed, 4.2 feet. You assume that in order to keep the passengers safe when the spring stops the train, the maximum stopping acceleration of the train, caused by the spring, is g/2. You are not sure about the train's weight, so you make a guess that a train might have a mass of 0.5 million kilograms. For the purpose of getting your answer, you assume that all frictional forces are negligible.


What is the maximum train speed?

i thought it would be a simple problem of just setting the kinetic energy = to the work done by the force of the spring

1/2 m^2 V = Force*mass*distance
4.2ft=1.28m
g/2=4.9

and i got v = 3.542 m/s... but it's wrong... anyone know what i did wrong?
 
Last edited:
Physics news on Phys.org
whereisccguys said:
i thought it would be a simple problem of just setting the kinetic energy = to the work done by the force of the spring
You have to find the expression for the spring constant. Assume that the spring was designed so that the maximum stopping deceleration for this train is g/2 . Since the stopping acceleration depends on the mass of the train hitting it, one would have to assume then, that the average mass of trains hitting it would be .5 million kg.

From Hooke's Law, the maximum deceleration occurs at maximum compression. From that you can determine the k of the spring. Then use your energy approach to figure out the maximum v. However, you have to use the correct expression for spring energy. It is not force x mass x distance. (Note: it turns out that the answer is independent of mass).

I get 2.5m/s

AM
 
ooo i understand... thanks a lot man
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
17
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
30
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K