Solving A^2 + 3A + I = 0: Inverse & -A-3I

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Discussion Overview

The discussion revolves around the problem of proving that a matrix \( A \) satisfying the equation \( A^2 + 3A + I = 0 \) is invertible, and exploring the expression for its inverse, specifically \( A^{-1} = -A - 3I \). The scope includes mathematical reasoning and matrix theory.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about factoring the equation due to the presence of a scalar, questioning whether \( A + 3 \) is defined for matrices.
  • Another participant suggests that factoring is permissible for matrices, citing the distributive law.
  • A different viewpoint proposes that an easier method to verify the inverse is to multiply \( A \) by the hypothesized \( A^{-1} \) and check if the product equals the identity matrix.
  • One participant points out that assuming \( A \) has an inverse in their work is circular reasoning, suggesting a different approach to demonstrate the relationship between \( A \) and its inverse.
  • Another participant concludes that the inverse of \( A \) is indeed \( -A - 3I \), affirming the earlier hypothesis.
  • A later contribution introduces a general principle regarding the invertibility of matrices that satisfy a polynomial with a non-zero constant coefficient.

Areas of Agreement / Disagreement

Participants express differing views on the validity of certain mathematical manipulations, particularly regarding the factoring of matrices and the assumptions made about the existence of an inverse. There is no consensus on the best approach to proving the invertibility of \( A \) or the correctness of the proposed inverse.

Contextual Notes

Some participants highlight the need for caution regarding assumptions about the existence of inverses and the definitions involved in matrix operations. The discussion reflects a range of mathematical reasoning and interpretations of matrix theory.

EvLer
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I have not come across this kind of problem, hence, not sure:

A is nxn, such that A^2 + 3A + I = 0
show that A is invertible and A^(-1) = -A-3I

So far I have this:

-A^2 - 3A = I

but now I am not sure if I can factor out A:

(-1)A [A + 3] = I

because I do not think that A + 3 is defined for matrices, since 3 is a scalar and not actually a vector.

Any hints are very much appreciated.
 
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3 A = 3 A I
 
Thanks I will try to work it out.
But just to confirm, it's wrong to factor in this case?
So far I have this solution, even though I factored afterall :redface:

(-1) A [A + 3] = I

(-1)A A^(-1) [A + 3] = I A^(-1)

(-1) [A + 3] = I A^(-1)

I^(-1) (-1)[A + 3] = I^(-1) I A^(-1)

-AI - 3I = A^(-1)

:confused:
 
Last edited:
Factoring is fine for matrices, they satisfy the distributive law:

P(Q + R) = PQ + PR
and
(P + Q)R = PR + QR
 
Oh, so I can represent 3A as 3 A I and then factor out A and end up with 3 I which is theoretically a matrix?
 
It's not just theoretically a matrix. :smile:
 
Anyways, an easier way to do the problem is to simply multiply A and the hypothesized A^-1, and check if you get I. (Don't forget to apply the polynomial identity A satisfies)

However, the work you did would be necessary if you weren't given a guess for A^-1.
 
Shish! I see it now :bugeye: .
Thanks!
 
However, you appear to be assuming that A has an inverse in your work which is what you want to prove.

What you can do is simply start with A^2 + 3A + I = 0, write that
as -A^2- 3A= I or (-A-3I)A= A(-A-3I)= I. Now what is the DEFINITION of inverse?
 
  • #10
so, then from this by DEFINITION of inverse:
AB=I=BA, where B is inverse, and given A(-A-3I)=I i can conclude that B in this case is (-A-3I).
I hope I am not making assumptions again...
Thank you all.
 
  • #11
Yes, of course. The inverse of A is just -A-3I.
 
  • #12
so the general principle is that if A satisfies a polynomial with non zero constant coiefficient then A is invertible. (over a field).

think about a diagonal matrix, with diagonal entries c1,...cn.

Then A satisfies (A-c1)(A-c2)...(A-cn), which has non zero constant term if and only if all the diagonal entries ci were non zero.
 

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