## the point of force application

1. The problem statement, all variables and given/known data
Hello everyone
I have got a cylindrical 6 axis force sensor (so I have the force Fx, Fy,Fz and torque Tx, Ty, Tz). Using these data I don’t know how I can find the point of force application.

2. Relevant equations

3. The attempt at a solution
I try this
The torque can be defined as the cross product I (Position vector) and F(force)
Tx,y,z=Ix,y,z ^Fx,y,z
So, I have 3 equations
Tx=IyFz-IzFy
Ty=IzFx-IxFz
Tz=IxFy-IyFx
But, when I solve the equation(in order to find Ix, Iy and Iz) , the variables in the equation vanish…

Do you have an idea how find this point.
Really thanks so much
Alexandra
Attached Images
 cylindrical.bmp (224.6 KB, 4 views)
 You can get the lever arms from the force and torque values.
 yes. if you see I try this is in "The attempt at a solution" but its not possible fin Ix, Iy and Iz

## the point of force application

Isn't torque r crossproduct F?
 yes I call I the Position vector.. in your case r .. the 2 arethe same..

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 Quote by The-alexandra But, when I solve the equation(in order to find Ix, Iy and Iz) , the variables in the equation vanish…
You can't expect it to give a specific vector for I. Suppose a solution is force G acting through the point r. Let s be any vector collinear with G. Then a force G acting through the point r+s is also a solution (indeed, the same solution really).
One way to fix that is to add the equation I.F = 0
 hi. if I understand you told me Ixyz . Fxyz = 0 in order to find a colinear vector. ??

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