Projectile montion Problem given the Inital Velocity and Angle to horizontalby keithc Tags: angle, horizontal, inital, montion, projectile, velocity 

#1
Dec612, 04:25 AM

P: 4

Hi All,
I am struggling to work out the following: Q: A football is kicked at an angle of 32.50 to the horizontal, with an initial velocity of 42m/s. Assume air resistance is negligible. A) Find the Balls Velocity at max Height B) The Balls Acceleratoin Vector at max Height I have so far worked out the following: The balls Max height has worked out to be 25.68 m The Travel time is 8.57 s and the Distance traveled is 303.5494m But not sure where to go with this next to figure out the A) and B) parts. I would very grateful for any help on this. Thx, K 



#2
Dec612, 04:42 AM

P: 939

If the method of solution is shown one can give help in a more suitable way.




#3
Dec612, 05:27 AM

P: 686

You don't need any of the 3 things you have figured out in order to get the 2 that you need. In fact, the 3 that you have figured out are quite a bit more complicated then the 2 you are asking about. You are WAAYY over thinking it.




#4
Dec612, 05:34 AM

P: 4

Projectile montion Problem given the Inital Velocity and Angle to horizontal
Hi All, thanks for looking and inputs. I am new to physics hence I have probably asked a silly question. But if don't ask I will never learn..
Thx again, K 



#5
Dec612, 06:00 AM

P: 686

So did you figure it out?




#6
Dec612, 06:05 AM

P: 4

Not yet !! Still hitting my head of this ball.. hehe.. I am lost as to where to go with my calc's. If I do I will post how I got there hopefully!!




#7
Dec612, 06:17 AM

P: 686

Start by breaking your initial velocity down into vertical and horizontal components. What is factors are going to influence each component while the football is in flight?




#8
Dec612, 06:48 AM

P: 4

I think I have worked out the velocity at the max height. Not too sure if I am correct or not.
The vertical velocity is 0 so that means that the horizontal velocity worked out by 42. cos 32.5 degs= 35.422 m/s is the same as the velocity at max height or am I totally off with this?? Thx K 



#9
Dec612, 11:03 AM

P: 686

Right on. Now the acceleration question is the easiest of all. Since we are neglecting air resistance there is only one other force to consider...



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