Need help on another optimization problem

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Homework Help Overview

The problem involves optimizing the volume of an open-top box created from a rectangular sheet of material by cutting squares from each corner. The dimensions of the sheet are specified, and the objective is to determine the size of the squares that maximizes the volume.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the expressions for length, width, height, and volume, with one participant expressing difficulty in factoring the derivative to find critical numbers. There are mentions of the second derivative to identify maxima and minima.

Discussion Status

Some participants have provided advice on finding the zeros of the derivative and suggested methods for determining maxima and minima. There is acknowledgment of the challenges faced with fractions and the limitations of calculator use during tests.

Contextual Notes

Participants note that this is a calculus problem rather than a physics problem, and there are constraints regarding calculator use on tests. The original poster indicates that this is a practice problem, suggesting a focus on understanding rather than immediate resolution.

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Problem: An open top box is constructed from a sheet of material by cutting equal squares from each corner and folding up the edges. If the sheet of material measures 14 inches by 9 inches, find the dimension x which represents the length of one side of the square that should be cut off so that the volume is maximized.

Work Done (Please Check!):

Length: [tex]L(x)=-2x+14[/tex]

Width: [tex]W(x)=-2x+9[/tex]

Height: [tex]H(x)=x[/tex]

Volume: [tex]V(x)=4x^{3}-46x^{2}+126x[/tex]

This is where I am stuck:

[tex]V'(x)=12x^{2}-92x+126[/tex]

I need to factor out the derivative so that I can get the critical numbers. Unless I did something wrong, from what I got above it's not going to be whole numbers. I always have problems with fractions. :redface:
 
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jzq said:
Problem: An open top box is constructed from a sheet of material by cutting equal squares from each corner and folding up the edges. If the sheet of material measures 14 inches by 9 inches, find the dimension x which represents the length of one side of the square that should be cut off so that the volume is maximized.

Work Done (Please Check!):

Length: [tex]L(x)=-2x+14[/tex]

Width: [tex]W(x)=-2x+9[/tex]

Height: [tex]H(x)=x[/tex]

Volume: [tex]V(x)=4x^{3}-46x^{2}+126x[/tex]

This is where I am stuck:

[tex]V'(x)=12x^{2}-92x+126[/tex]

I need to factor out the derivative so that I can get the critical numbers. Unless I did something wrong, from what I got above it's not going to be whole numbers. I always have problems with fractions. :redface:


this is more of a calc problem than physics

get a ti89 :D

i get the zeroes as 5.88 and 1.79...if you take the 2nd derivative you can find out which is the max and which is the min...
 
Thanks for your advice and solution.

P.S. No offense, this forum deals with all subjects even though it is called Physics Forums. This is college homework so that is why I posted this here. If you look at other threads in this section, you will also find other calculus problems. And about the TI-89, I can't use calculators on tests.
 
Last edited:
jzq said:
Thanks for your advice and solution.

P.S. This forum deals with all subjects. This is college homework so that is why I posted this here. If you look at other threads in this section, you will also find other calculus problems. And about the TI-89, I can't use calculators on tests.

if she gives you problems like that she better!

of course if she gives you a similar problem it will easily be factored

basically you just find the zeroes of the derivative function...either with an 89 or using factoring
 
Yea, I think it's ridiculous that we can't use calculators on tests. Fortunately, this is only a practice problem. Hopefully they won't have something like this on the test. Thanks again!
 

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