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Degrees of freedom

by Jhansi1990@gma
Tags: degrees, freedom
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Jhansi1990@gma
#1
Feb8-13, 03:43 AM
P: 4
What are the number of degrees of freedom of
1)a square sheet moving in XY plane
2)a triangular lamina moving freely in XY plane
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mfb
#2
Feb8-13, 01:26 PM
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P: 11,631
This looks like homework: What did you find out so far?
Jhansi1990@gma
#3
Feb10-13, 02:48 PM
P: 4
A square is composed of many particles with the constraint that distance between every particle is the fixed.so such a square is moving in XY plane.

if i consider two particles they have 4-1 =3degree of freedom(one is subtracted due to constraint that distance between particles are fixed).if i consider third particle it is defined by two co-ordinates and two constraints and therefore no degree of freedom.....the same for fourth fifth and so on.....

so my answer is three

and i dont find any difference in this respect with a triangular lamina......



I do not know the answer to the question.......please comment on this and say if you have any other opinion.

mfb
#4
Feb10-13, 03:38 PM
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P: 11,631
Degrees of freedom

Those 3 degrees of freedom just fix the current position of the square. What about its movement?
Jhansi1990@gma
#5
Feb10-13, 03:45 PM
P: 4
if i get generalized co-ordinates i can calculate co-ordinate velocities from it
mfb
#6
Feb10-13, 03:46 PM
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P: 11,631
Is that related to the original question?
What do you mean with "get"?
Jhansi1990@gma
#7
Feb10-13, 04:12 PM
P: 4
The question does not ask that .But i told a general principle.For example a simple pendulum which is oscillating in a plane.since its moving along the arc of a circle(distance from orgin is fixed) it has only one degree of freedom....theta.....which is the angle dat the string makes with vertical.......so if i know theta as a function of time.....i can differentiate "theta" to find generalised co-ordinate velocity


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