Register to reply

Will free electrons experience its own electric/magnetic field?

Share this thread:
iaMikaruK
#1
Feb19-13, 11:51 PM
P: 11
Hi, everyone :)
Recently I've read a paper and found in that paper that the authors derived the wavefunction of moving free electrons from its own electric and magnetic field. It was quite a shock to me.
So, for free electrons without external electric and magnetic field, why additional "self-interaction" terms were added to the Hamiltonian? I don't remember any textbook has included such terms in Dirac equation for free electrons.
Thank you very much!
Phys.Org News Partner Physics news on Phys.org
Step lightly: All-optical transistor triggered by single photon promises advances in quantum applications
The unifying framework of symmetry reveals properties of a broad range of physical systems
What time is it in the universe?
Simon Bridge
#2
Feb20-13, 12:15 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
Welcome to PF;
One way of looking at it is that there is always a probability that the electron has emitted a virtual photon (or how else does it interact with other electrons) which means there is a probability that it can interact with that photon. This means the electron is interacting with itself.

Have a look at the self-interaction bits concerning "renormalization".
http://en.wikipedia.org/wiki/Renormalization

Some care is needed - in QED you don't get an electron in a universe all by itself - that would mean there is nothing to measure it for eg. It has to come from some interaction and be going to another interaction.
iaMikaruK
#3
Feb20-13, 12:40 AM
P: 11
Quote Quote by Simon Bridge View Post
Welcome to PF;
One way of looking at it is that there is always a probability that the electron has emitted a virtual photon (or how else does it interact with other electrons) which means there is a probability that it can interact with that photon. This means the electron is interacting with itself.

Have a look at the self-interaction bits concerning "renormalization".
http://en.wikipedia.org/wiki/Renormalization

Some care is needed - in QED you don't get an electron in a universe all by itself - that would mean there is nothing to measure it for eg. It has to come from some interaction and be going to another interaction.
Thanks for the reply.
Anyhow, the interaction due to the virtual photon should not enter the Hamiltonian as [itex]e\boldsymbol{\sigma}\cdot\mathbf{A}[/itex],[itex]\boldsymbol{\mu}_e\cdot\mathbf{B}[/itex] and [itex]-eV[/itex]? Sorry I know little of QED.
In that paper, the authors simply added [itex]e\boldsymbol{\sigma}\cdot\mathbf{A}[/itex] and [itex]-eV[/itex] to the Hamiltonian, where [itex]\mathbf{A}[/itex] and [itex]V[/itex] are fields created by the moving free electrons themselves in the laboratory frame, as a correction. I don't understand why they include the fields created by the free electrons as interactions.

Simon Bridge
#4
Feb20-13, 12:59 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
Will free electrons experience its own electric/magnetic field?

The interaction does not enter in at the Hamiltonian level as such - but in the perturbation theory. Did you read the link?

QED = Quantum Electrodynamics ... the field theory of electrons and photons. Nobel prize for Feynman and some people less famous.

To be able to address your specific case, though, I need the reference.
If the term is added "as a correction" they should tell you what they are correcting.

If there is a charge density, then the electrons are not "free" electrons - they experience each other's fields.
iaMikaruK
#5
Feb20-13, 03:29 AM
P: 11
Quote Quote by Simon Bridge View Post
The interaction does not enter in at the Hamiltonian level as such - but in the perturbation theory. Did you read the link?

QED = Quantum Electrodynamics ... the field theory of electrons and photons. Nobel prize for Feynman and some people less famous.

To be able to address your specific case, though, I need the reference.
If the term is added "as a correction" they should tell you what they are correcting.

If there is a charge density, then the electrons are not "free" electrons - they experience each other's fields.
Sorry, I cannot open the wiki page because of some reasons. But it works for me now.
I've sent the reference link to you by private message. Thank you.
andrien
#6
Feb20-13, 05:43 AM
P: 1,020
Quote Quote by iaMikaruK View Post
Hi, everyone :)
Recently I've read a paper and found in that paper that the authors derived the wavefunction of moving free electrons from its own electric and magnetic field. It was quite a shock to me.
So, for free electrons without external electric and magnetic field, why additional "self-interaction" terms were added to the Hamiltonian? I don't remember any textbook has included such terms in Dirac equation for free electrons.
can you give a link to this paper.
iaMikaruK
#7
Feb20-13, 05:55 AM
P: 11
Quote Quote by andrien View Post
can you give a link to this paper.
I've sent you the link in private message.
Simon Bridge
#8
Feb20-13, 06:15 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
I've sent you the link in private message.
Please don't do that - if you want public replies, you should give public information.
Here's the link I got:
S. M. Lloyd, M. Babiker, J. Yuan, and C. Kerr-Edwards
Electromagnetic Vortex Fields, Spin, and Spin-Orbit Interactions in Electron Vortices
Electron vortices are shown to possess electric and magnetic fields by virtue of their quantized orbital angular momentum and their charge and current density sources. The spatial distributions of these fields are determined for a Bessel electron vortex. It is shown how these fields lead naturally to interactions involving coupling to the spin magnetic moment and spin-orbit interactions which are absent for ordinary electron beams. The orders of magnitude of the effects are estimated here for ȧngström scale electron vortices generated within a typical electron microscope.
Phys. Rev. Lett. 109, 254801 (2012) [5 pages]

The article does not seem to deal with free electrons at all.
iaMikaruK
#9
Feb20-13, 06:26 AM
P: 11
Quote Quote by Simon Bridge View Post
Please don't do that - if you want public replies, you should give public information.
Here's the link I got:
S. M. Lloyd, M. Babiker, J. Yuan, and C. Kerr-Edwards
Electromagnetic Vortex Fields, Spin, and Spin-Orbit Interactions in Electron Vortices
Electron vortices are shown to possess electric and magnetic fields by virtue of their quantized orbital angular momentum and their charge and current density sources. The spatial distributions of these fields are determined for a Bessel electron vortex. It is shown how these fields lead naturally to interactions involving coupling to the spin magnetic moment and spin-orbit interactions which are absent for ordinary electron beams. The orders of magnitude of the effects are estimated here for ȧngström scale electron vortices generated within a typical electron microscope.
Phys. Rev. Lett. 109, 254801 (2012) [5 pages]

The article does not seem to deal with free electrons at all.
Well, it does deal with free electrons. The electric field [Eq.(9)] and magnetic field [Eq.(10)] of the vortex beam are all evaluated from the solution of Schrodinger equation of free electrons [Eq.(1)]. Then ,the authors claim that "To determine how electric and magnetic fields interact
with the electron vortex, we start from the Dirac equation in the presence of electromagnetic fields, with vector and scalar potentials A and [itex]\Phi[/itex]. These potentials can be external, or they could be those corresponding to the vortex fields derived above."
What puzzling me is that why these electric and magnetic fields derived from a vortex beam interact with the vortex beam itself?
Simon Bridge
#10
Feb20-13, 06:52 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
The beam is made up of individual electrons which individually interact with the fields of all the other electrons. Ergo - the beam interacts with it's own field.
iaMikaruK
#11
Feb20-13, 07:22 AM
P: 11
Quote Quote by Simon Bridge View Post
The beam is made up of individual electrons which individually interact with the fields of all the other electrons. Ergo - the beam interacts with it's own field.
This argument is reasonable but I don't think it's applicable here.
I just made a simple calculation. For a 200 kV electron, its speed is about 0.7c. Assuming that the cross-section of the beam is 1x1 angstrom^2 and the current density about 1 nA taken from the reference, then we can calculate the density of electrons. The calculation result is about 1 nA*1s / (0.7c*1 angstrom*1 angstrom*1s)=3x10^(-9) electrons/angstrom^3. So I think it is of very low probability for two electrons to interact with each other.
ZapperZ
#12
Feb20-13, 07:37 AM
Emeritus
Sci Advisor
PF Gold
ZapperZ's Avatar
P: 29,238
Quote Quote by iaMikaruK View Post
This argument is reasonable but I don't think it's applicable here.
I just made a simple calculation. For a 200 kV electron, its speed is about 0.7c. Assuming that the cross-section of the beam is 1x1 angstrom^2 and the current density about 1 nA taken from the reference, then we can calculate the density of electrons. The calculation result is about 1 nA*1s / (0.7c*1 angstrom*1 angstrom*1s)=3x10^(-9) electrons/angstrom^3. So I think it is of very low probability for two electrons to interact with each other.
You should learn a little bit about beam physics for particle accelerators. Here, the charge per bunch, and the size of each bunch can be of significant importance due to space-charge effects. Such an effect is, by definition, the bunch's self-interaction. In free-electron lasers, this interaction causes an increase in the beam emittance, which is something we don't want.

Zz.
iaMikaruK
#13
Feb20-13, 09:15 AM
P: 11
Quote Quote by ZapperZ View Post
You should learn a little bit about beam physics for particle accelerators. Here, the charge per bunch, and the size of each bunch can be of significant importance due to space-charge effects. Such an effect is, by definition, the bunch's self-interaction. In free-electron lasers, this interaction causes an increase in the beam emittance, which is something we don't want.

Zz.
I agree that for a contiunous emittion of electrons, the electrons will interact with each other. I tried to calculate the space-charge effect in electron microscopy but failed to get a reasonable value.
But I still have the question that the Hamiltonian of single electron, if we have taken the space-charge effect into consideration, will still have the form as described in the reference?
Thanks very much.
iaMikaruK
#14
Feb20-13, 08:17 PM
P: 11
Quote Quote by ZapperZ View Post
You should learn a little bit about beam physics for particle accelerators. Here, the charge per bunch, and the size of each bunch can be of significant importance due to space-charge effects. Such an effect is, by definition, the bunch's self-interaction. In free-electron lasers, this interaction causes an increase in the beam emittance, which is something we don't want.

Zz.
I reread the paper and found that the authors claimed that "Note that the fields are due to the charge and current arising from the flow of electrons associated with the vortex and we assume that electron-electron interactions are negligible, thus ignoring the Boersch effect" Any idea?
Simon Bridge
#15
Feb21-13, 01:34 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
the fields are due to the charge and current arising from the flow of electrons associated with the vortex ... I would read that as neglecting direct, individual, e-e interactions, but the vortex comes from someplace.

It's a bit like pointing out that the e-e B-field interactions for a current is negligible when dealing with the effect of the B-field due to the current.

It's still not individual electrons here ... if you started your model as individual free electrons, you'd need to correct for the fact that there are other things going on.
That's how it works - you start with a simple model that has easy math and include corrections as more different things get taken into account.

But also - bear in mind what ZapperZ wrote.
iaMikaruK
#16
Feb21-13, 02:33 AM
P: 11
Quote Quote by Simon Bridge View Post
the fields are due to the charge and current arising from the flow of electrons associated with the vortex ... I would read that as neglecting direct, individual, e-e interactions, but the vortex comes from someplace.

It's a bit like pointing out that the e-e B-field interactions for a current is negligible when dealing with the effect of the B-field due to the current.

It's still not individual electrons here ... if you started your model as individual free electrons, you'd need to correct for the fact that there are other things going on.
That's how it works - you start with a simple model that has easy math and include corrections as more different things get taken into account.

But also - bear in mind what ZapperZ wrote.
A single electron can form a vortex itself. So the vortex needs not come from someplace.
So you are suggesting that two vortex beams are interacting with each other via electric field? But as I recalled the Boersch effect, it was treated completely as electric field interaction between electrons, for example: J. Vac. Sci. Technol. 16, 1676 (1979). And this effect was also neglected by the authors. So what I understand is that the authors have neglected both the electric and magnetic field interactions between individual electrons. Is my understanding correct?

Then what I have come to conclude:
(1) I wrote down a Schrodinger/Dirac equation for a free electron and find the solution;
(2) I evaluated the electric and magnetic field from the solution;
(3) I should add the electric and magnetic field self-interaction back to the Hamiltonian although there is no external field or electron-electron interaction?
Simon Bridge
#17
Feb21-13, 03:41 AM
Homework
Sci Advisor
HW Helper
Thanks
Simon Bridge's Avatar
P: 12,876
Self interactions occur for free particles in the perturbation theory. You need to learn more about self-interactions and renormalizations to understand how this works.

When modelling a beam, there will be correction terms to account for the real circumstances of the beam. You need to look deeper into the nature of the beam being used in the experiment to understand more what the authors are describing.

If you still don't believe the answers you have been getting - I suggest writing to the authors and asking them what they are talking about.
iaMikaruK
#18
Feb21-13, 04:00 AM
P: 11
Quote Quote by Simon Bridge View Post
Self interactions occur for free particles in the perturbation theory. You need to learn more about self-interactions and renormalizations to understand how this works.

When modelling a beam, there will be correction terms to account for the real circumstances of the beam. You need to look deeper into the nature of the beam being used in the experiment to understand more what the authors are describing.

If you still don't believe the answers you have been getting - I suggest writing to the authors and asking them what they are talking about.
Here I listed three references. The first two use Dirac equation and the last one mass-corrected Schrodinger equation. But they all do not taken the electric and magnetic field self-interaction into Hamiltonian. The experimental set-up are the same as in PRL 109, 254801 (2012).
[1] PRL 99, 190404 (2007).
[2] PRL 107, 174802 (2011).
[3] Ultramicroscopy 111, 1461-1468 (2011).

I've written a mail to the author but got no response by now.


Register to reply

Related Discussions
Electrons in a magnetic/electric field Introductory Physics Homework 1
Does a stationary electron in magnetic field experience Lorentz force? Introductory Physics Homework 2
Dynamic Magneto electric conductivity tensor for free electrons Advanced Physics Homework 0
Electrons magnetic field General Physics 2
Electric field created in a bar by electrons deflected in a magnetic field Introductory Physics Homework 1