Calc Q: Line Int. Depends on Area, Not Placement

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Homework Help Overview

The discussion revolves around a line integral defined over the boundary of a rectangular region in R2, specifically examining how its value depends solely on the area of the rectangle rather than its position in the plane.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the applicability of Green's Theorem to the problem, with some expressing uncertainty about its relation to the area of the rectangle. There are attempts to establish a parametrization of the boundary and considerations of how to incorporate area into the integral evaluation.

Discussion Status

Several participants agree that Green's Theorem is relevant and potentially the most straightforward approach to tackle the problem. However, there is a lack of consensus on the initial steps to take, with some expressing confusion about the theorem's application.

Contextual Notes

Some participants indicate a need for clarification on the relationship between the line integral and the area, as well as the specific conditions under which Green's Theorem can be applied to this scenario.

Sneaksuit
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Anyone know how to do this question?
Let C be the boundary of any rectangular region in R2. Show that the value of the line integral
[tex]\oint (x^2 y^3 -3y)dx + x^3 y^2 dy[/tex]
depends only on the area of the rectangle and not on its placement in R2.
 
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Can you think of a good way to start the question (I'm assuming you've learned a few useful theorems on line integrals)?

BIG HINT: What theorem will let you incorporate the area of the rectangle into the evaluation of the integral?
 
Last edited:
Well, we are working on Green's Theorem right now but i don't remember it incorporating the area of a rectangle. So, to answer your question...no, i don't even know where to begin.
 
You must parametrize your boundary:
Let "t" be in some interval, so that the perimeter of the rectangle is given as some path (x(t),y(t)). Note that [tex]dx=\frac{dx}{dt}dt[/tex]
similarly for dy, and that on regions where say x=constant, dx must equal 0.
 
Green's theorem applies to rectangles, and any curves that have a finite number of corners and don't cross themselves.
 
Crosson said:
Green's theorem applies to rectangles, and any curves that have a finite number of corners and don't cross themselves.
I din't imply that you couldn't use Green's theorem.
Of course you can, and it is probably the easiest way to do this.

(I thought to be "creative" in giving an alternative way of doing this, but reviewing the problem, following my earlier "advice" is simply inadvisable..)
 
Last edited:
Green's Theorem is definitely the way to go for this problem. Just apply it and see where it leads you.
 

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