Calculating Velocity for Burn Patients on a Rotating Space Station

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Homework Help Overview

The discussion revolves around calculating the period of rotation for a doughnut-shaped space station designed for treating burn patients. The patients are positioned at a distance of 200 meters from the axis of rotation, and the goal is to achieve a radial acceleration equal to 1/10 of the acceleration due to gravity.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between centripetal acceleration and velocity, questioning how to derive velocity from the given acceleration. There is discussion about the connection between velocity and the period of rotation, with attempts to express these relationships mathematically.

Discussion Status

Some participants have provided guidance on the mathematical relationships involved, while others express confusion about the calculations. Multiple interpretations of the problem are being explored, particularly regarding the correct application of formulas to find velocity and period.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available and the assumptions that can be made about the system.

IamatWork
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consider a rotating doughnut shaped space station used to treat burn patients. the patients are located on the outer perimeter of the station at a distance of 200 meters from the axis of rotation. calculate the period of rotation that would produce a radial acceleration equal to 1/10 the acceleration due to gravity (.98 meters/second2).

this appears to me as a centripetal acceleration problem...a=v2/r, because the acceleration is directed toward the center, but how do i get my velocity? am i going in the right direction? thanks
 
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You are on the right track.
Now, you have gotten that [tex]\frac{v^{2}}{R}=\frac{g}{10}[/tex]
This has only 1 unknown, v.

Secondly, how is v related to the period?
 
well, velocity is m/s. if i solve this equation i get v2=.0049/s2, which is no good!
 
What are you talking about?
You get [tex]v=\sqrt{\frac{gR}{10}}[/tex]
 
which gives you a velocity of 14 m/s. however, that does not help you find the period using centripetal accelaration
 
Sure it does: What is the relation between the velocity you found and the period?
 
velocity is 14m/s and one period is 2pi...therefore the period is equal to 87.9 seconds
 
never mind that doesn't work
 
i got it..one period equals 2 pi and the lenth of arc s/r equals the circumference of the station...thanks for your help
 

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