Blocks being pulled by a string

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Homework Help Overview

The discussion revolves around a physics problem involving tension and force in a system of three identical blocks connected by strings, being pulled along a frictionless surface. Participants are exploring the relationships between force, tension, and acceleration in this context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the force and acceleration of the blocks based on the tension in the strings. Some participants discuss the relationship between the total force, tension, and acceleration, while others verify calculations and reasoning.

Discussion Status

The discussion has seen some productive exchanges, with participants confirming the relationships between force, tension, and acceleration. There is a general agreement on the approach taken, but no explicit consensus on the final expressions has been reached.

Contextual Notes

Participants are working under the assumption that the blocks are identical and that the surface is frictionless, which influences their calculations and reasoning about the system's dynamics.

alexialight
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I'm just starting to get my head around the concepts of Tension and Force but I'm stuck on this question, I was wondering if anyone could help me out?

Q: 3 identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F. The magnitude of the tension in the string between blocks B and C is T. Assume that each block has mass m.

i> What is the magnitude of the force? (Expressed in terms of T)
ii> What is the magnitude of the acceleration of the three blocks (in terms of m and F)?

I worked out the acceleration on block B (T/(2*m)) but don't know what to do next. I'd really appreciate any help with this.
 

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The acceleration is the same for the entire system. So the force must be (m1 + m2 + m3)*a

hope that helps
 
I think it does... that would make the Force 3/2*T right?
So in terms of m and F, the acceleration would be F/3m ?
 
Last edited:
Yes, you are right.

[tex]F - T = m_ca[/tex],

or

[tex]F = T + m_ca = T + m(\frac{T}{2m}) = \frac{3}{2}T[/tex]
 
Awesome - Thanks a lot
 

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