Lower wishbone stress calculation problem

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SUMMARY

The discussion focuses on the stress calculation for a front suspension assembly designed for a locost sports car using Pro/ENGINEER (Pro/E). The user has calculated the force at the suspension bracket to be 5849.03N and the second moment of area (I) as 2 x 10-8 m2. Key questions include the correctness of the force at the suspension bracket, the definition of the bending moment (M), and whether to adjust the second moment of area for two bars side by side. The consensus is to model the tube as a beam and consider dynamic analysis for accurate stress evaluation.

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Hi,
I was wondering if some one could help me with my stress calculation problem.

I have designed a front suspension assembly for a locost sports car on pro/e. I would like to validate my design by performing some bending moment calculations of the part and then comparing the stress found in a 3g bump situation to that of the yield stress.
I have performed some of the calculations so far but don't know if i am going in the right direction and what to do next. I'm working in SI units.

I have simplified the v shaped wishbone to one length of tubing.
length = 0.3429m

One end is connected to the chassis and rotates about the bracket.

The other is connected to the lower ball joint that connects to the wheel and upright assembly.

The suspension spring and damper bracket centre is located 0.08407m from the lower balljoint.

The force at the wheel end is the reaction force of half the axle wieght + 3g
weight of axle = 300kg /2 = 150kg x 3g = 4414.5N
In a 3g bump the wishbone will rotate up wards and the damper would compress right up to the bump stops and so effectively would be stationary. therefore if clockwise moments = anti clockwise then..
4414.5N x 0.3429 = A x 0.2588

( 0.2588 is 0.3429 - 0.08407)

therfore A (force at suspension bracket =
5849.03N

I found the second moment of area to be..
I = 2 x10-8 m2

and y = 0.0127m

so if sigma = My/I then i should be able to find sigma and see if is below the yeild stress of the steel

This is how far i got with the calculations

Is the force at the suspension bracket correct?
What is M ?
I wanted the calculations to be for two bars side by side so to get the corect stress do i change the second moment of area to the value for two bars or,
perform the calcs for one bar and then x 2?
 
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Suspensions are a complicated thing to anylize because of all of the forces you have to account for. Plus, you're doing static calculations. If you really want to look at the
actual stresses, you're going to have to do a dynamic analysis.

For the simplified model, I would look at modeling the tube as a beam with a ball and socket at one end andthe other free with a rigid support at the point of shock absorber attachment. I would also look at the moment you are using. At the point the strut bottoms out, you are not going to be seeing the axle weight, you'll be seeing the inertial load from the mass of the vehicle itself, plus the load created by the strut compression. You're going to have to estimate the force distribution to the wheels and then you will have an idea as to what the moment about the strut attachment point is.

See if you can't get your model to someone with ANSYS.
 


Hi there,

It sounds like you have made some good progress on your stress calculation problem. It is always a good idea to validate your design through calculations before moving on to physical testing.

To answer your questions, the force at the suspension bracket seems to be correct based on the information you have provided. However, it would be helpful to have a clear image or diagram of your assembly to confirm this.

In terms of the "M" in the equation, this represents the bending moment. It is the product of the force and the distance from the point of rotation (in this case, the bracket) to the point where the force is applied (in this case, the wheel end). It is important to make sure you are using the correct distance in your calculation.

As for the second moment of area, it should be calculated based on the cross-sectional area of your tubing. If you are using two bars side by side, you would need to consider the combined cross-sectional area in your calculation. You could also perform the calculations for one bar and then multiply by two, but make sure you are using the correct value for the second moment of area in this case.

I hope this helps and good luck with your calculations!
 

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