Let omega=x dx+y dy+z dz be a 1-form

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Discussion Overview

The discussion revolves around the computation of the Lie derivative of a 1-form, specifically omega = x dx + y dy + z dz, on R^3, with respect to a vector field X = (x, y, z). Participants explore the application of Cartan's formula and the process of computing the pullback of omega under the flow generated by X.

Discussion Character

  • Technical explanation
  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant presents an exercise involving the computation of L_X(omega) and suggests that the flow generated by X is (e^t, e^t, e^t), expressing uncertainty about how to proceed with the pullback and differentiation.
  • Another participant proposes applying Cartan's formula, stating that L_X(omega) = i_X domega + d(i_X omega), where domega is the exterior derivative and i_X(omega) is the antiderivation.
  • Some participants note that the thread is quite old and question the relevance of the discussion, suggesting that the original poster may no longer need assistance.
  • There is a humorous remark about the nature of answering old questions, comparing it to "dating a middle-aged virgin," which introduces a light-hearted tone but does not contribute to the technical discussion.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of the thread due to its age, with some finding value in revisiting old questions while others question the practicality of doing so. The technical aspects of the computation remain unresolved, with no consensus on the best approach to take.

Contextual Notes

The discussion lacks clarity on the specific steps required to compute the pullback and the differentiation at t=0, leaving some assumptions and mathematical details unaddressed.

carbis
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Here an exercise I found between old exams:
Let omega=x dx+y dy+z dz be a 1-form on R^3 and X=(x,y,z) a vectorfield.
Compute L_X(omega) as derivative of the pullback of omega under the flow generated by X.
I think the flow generated by X is (e^t,e^t,e^t), but I don't know how to proceed (computing the pullback, inserting omega en differentating at t=0.
Anyone? :smile:
 
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carbis said:
Here an exercise I found between old exams:
Let omega=x dx+y dy+z dz be a 1-form on R^3 and X=(x,y,z) a vectorfield.
Compute L_X(omega) as derivative of the pullback of omega under the flow generated by X.
I think the flow generated by X is (e^t,e^t,e^t), but I don't know how to proceed (computing the pullback, inserting omega en differentating at t=0.
Anyone? :smile:



Apply Cartan's formula: [tex]L_X(\omega)=i_X d\omega+d(i_X\omega)[/tex], [tex]d\omega[/tex] being the exterior derivative and [tex]i_X(\omega)[/tex] the antiderivation.
 


While this is a nice answer, the thread is over four years old, and it has been more than two years since the original poster lat signed in.
 


George Jones said:
While this is a nice answer, the thread is over four years old, and it has been more than two years since the original poster lat signed in.


Yeap, I guess Carbis won't be needing it for his homework anymore.


Anyhow, I enjoy digging up interesting questions that no-one ever bothered to answer...
It's something like dating a middle-aged virgin.
(Will this get me banned? damn...)
 


Reb said:
Yeap, I guess Carbis won't be needing it for his homework anymore.


Anyhow, I enjoy digging up interesting questions that no-one ever bothered to answer...
It's something like dating a middle-aged virgin.
(Will this get me banned? damn...)

I think answering old questions is good because when someone Googles the question, then they'll be more likely to find the answer.
 

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