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Fractional Equations

by homegrown898
Tags: equations, fractional
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homegrown898
#1
Apr3-05, 07:29 PM
P: 16
Because I can't write squared, if x is squared, I will just write it like this: xsquared

x/x +2 MINUS x/xsquared - 4 = x+3/x+2

I get an LCD for each fracton and then I subtract getting this:

xsquared - 2x MINUS x/xsquared - 4 = (x+3)(x-2)/xsquared - 4

What do I do now?

If you don't understand this just ask me to scan it
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Data
#2
Apr3-05, 07:35 PM
P: 998
I suppose you mean

[tex] \frac{x}{x+2} - \frac{x}{x^2-4} = \frac{x+3}{x+2} \Longrightarrow \frac{x^2 - 3x}{x^2 - 4} = \frac{(x+3)(x-2)}{x^2 - 4}[/tex]

which is fine.
Moo Of Doom
#3
Apr3-05, 07:37 PM
P: 367
Quote Quote by homegrown898
If you don't understand this just ask me to scan it
Or just learn LaTeX.

I'm not quite sure what you mean. I surmise it is something like this:

[tex]
\frac{x}{x+2}-\frac{x}{x^2-4}=\frac{x+3}{x+2}[/tex]

If it's not right, let me know.

EDIT: Yarr, Data got there before I did...

homegrown898
#4
Apr3-05, 07:40 PM
P: 16
Fractional Equations

Quote Quote by Data
I suppose you mean

[tex] \frac{x}{x+2} - \frac{x}{x^2-4} = \frac{x+3}{x+2} \Longrightarrow \frac{x^2 - x}{x^2 - 4} = \frac{(x+3)(x-2)}{x^2 - 4}[/tex]

which is fine.
Moo, that was right what you posted

And that is where I got but the instructions are to solve

Is that a solution to it?
Data
#5
Apr3-05, 07:42 PM
P: 998
Note that there is a small error in the thing you quoted, which I've corrected now.

To solve, multiply [itex]x^2-4[/itex] through both sides, expand on the right, and see what you get.
homegrown898
#6
Apr3-05, 07:48 PM
P: 16
Quote Quote by Data
Note that there is a small error in the thing you quoted, which I've corrected now.

To solve, multiply [itex]x^2-4[/itex] through both sides, expand on the right, and see what you get.
I don't want to learn Latex right now because it will take too long but I'll learn it for the future.

This is what I'm getting:

xsquared - 2x - x = xsquared + x - 6

I subtract xsquared on each side to cancel them out getting:

-2x - x = x - 6

I then subract x from each side getting

-3x - x = -6

Then I subract the x

-4x = -6

Did I mess up?
Moo Of Doom
#7
Apr3-05, 07:59 PM
P: 367
Quote Quote by homegrown898
Did I mess up?
Looks right to me.


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