Intersection coordinates are my points right?

[aisha]

Hi can someone please check that my points of intersection are correct?

The question was determine the coordinate of the intersection point of

$$\frac {(x-3)^2} {9} + \frac {y+2)^2} {4} =1$$ and $$y=2x-3$$

I after putting the second equation into the first and then expanding and solving for x and y I got my two intersection points to be

(1.33,-0.34) and (0.169,-2.66) These values work well when plugged into the equation both coordinates equal 36 from the first equation when denominators are eliminated.

I wanted to check this with the graphing calculator but was having a hard time putting the first equation into y= form. Can someone help me out a little please

 

[dextercioby]

With what?If you got those points (which was what the problem asked),then you're done with it.

Can't your software plot implicit equations?My Maple can.

Daniel.

 

[what]

you did it right no need to graph it'd be a waste of time. If you really wanted to you can graph this in a calculator(i'm assuming you have TIsomething), you need to put one of the equations in two pieces one positive square root and the other negative.