Mastering Significant Figures in Logarithms: A Comprehensive Guide

  • Thread starter Thread starter mathzeroh
  • Start date Start date
  • Tags Tags
    Significant figures
Click For Summary

Homework Help Overview

The discussion revolves around the application of significant figures in logarithmic calculations, particularly focusing on the rules governing the mantissa and characteristic of logarithms. Participants are exploring how these rules apply to both logarithms and antilogarithms, as well as rounding numbers to a specified number of significant figures.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the relationship between the number of significant figures in the original number and the resulting logarithmic values. They are particularly confused about why certain logarithmic results appear to have more significant figures than expected based on the original numbers. There is also discussion about the rounding of numbers and the rules that apply to significant figures in that context.

Discussion Status

Some participants have provided clarifications regarding the rules of significant figures in logarithms and antilogarithms, while others are still grappling with the implications of these rules. There is an ongoing exploration of the definitions and applications of mantissa and characteristic in logarithmic contexts.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may impose specific rules or expectations about the treatment of significant figures. There is a noted confusion about the application of these rules, particularly in relation to rounding and the significance of digits in different parts of logarithmic expressions.

mathzeroh
Messages
98
Reaction score
0
significant figures help needed badly!

hows everyone doing in this fine evening? :biggrin:

ok i just had some questions on "sig figs" as the pros call it (unfortunately that's not me :frown: :cry: ) ok, i'll try to explain as clearly as i can here:

in this manual i have that explains sig figs, it says the following about Siginificant Figures in Logarithms:

...The characteristic consists of the digits to the lft of the decimal point and the mantissa consists of the digits to the right of the decimal point. the mantissa of a log should have the same number of sig. figs. as does the original number. Some esamples are:

log 2=0.3 (1sig fig in 2)
log 2.0=0.30 (2 sig figs in 2.0)
log 2.00=0.300 (3 sig figs in 2.00
)
log 2.0 X 10^4=4.30 (2 sig figs in 2.0)
log 2.00 X 10^(-5)=-4.699 (3 sig figs in 2.00)




now my questions concern the red bold faced part of the above examples. if it says that there's "3 sig figs in 2.00" then why does it report a four sig fig carrying number -4.699?? :rolleyes: :confused:

it said that the same rule was applied to antilogs, but again, same problem a little further down in the examples:

... antilog 3.4771 = 3.000 X 10^3 (4 sig figs in the mantissa)

uh yea i see that but so what?? isn't it supposed to have FIVE sig figs because of the "characteristic"??


also, can somebody please tell me if i did these correctly:

Round to four sig figs:

273.15 -> 273.2 *(bcuz the "1" is an odd number, you would round up to the nearest even number, right? and if it was already an even number followed by a 5 and nothing else following the 5, you would leave it alone as a "1" and just drop the five, right??
12.652 -> 12.65
19.9743 -> 19.97
4.32156 -> 4.322
0.019807 -> 0.01981



Thanks!
 
Last edited:
Physics news on Phys.org
mathzeroh said:
hows everyone doing in this fine evening? :biggrin:

ok i just had some questions on "sig figs" as the pros call it (unfortunately that's not me :frown: :cry: ) ok, i'll try to explain as clearly as i can here:

in this manual i have that explains sig figs, it says the following about Siginificant Figures in Logarithms:

...The characteristic consists of the digits to the lft of the decimal point and the mantissa consists of the digits to the right of the decimal point. the mantissa of a log should have the same number of sig. figs. as does the original number. Some esamples are:

log 2=0.3 (1sig fig in 2)
log 2.0=0.30 (2 sig figs in 2.0)
log 2.00=0.300 (3 sig figs in 2.00
)
log 2.0 X 10^4=4.30 (2 sig figs in 2.0)
log 52.00 X 10^(-5)=-4.699 (3 sig figs in 2.00)




now my questions concern the red bold faced part of the above examples. if it says that there's "3 sig figs in 2.00" then why does it report a four sig fig carrying number -4.699?? :rolleyes: :confused:
The mantissa (digits after the decimal) should have the same number of digits: 699 is 3 digits.

it said that the same rule was applied to antilogs, but again, same problem a little further down in the examples:

... antilog 3.4771 = 3.000 X 10^3 (4 sig figs in the mantissa)

uh yea i see that but so what?? isn't it supposed to have FIVE sig figs because of the "characteristic"??

According to the rule at the top of your posted it is supposed to have 4 digits because the mantissa has 4 digits (you shouldn't be taking the number of digits of the characteristic)

also, can somebody please tell me if i did these correctly:

Round to four sig figs:

273.15 -> 273.2 *(bcuz the "1" is an odd number, you would round up to the nearest even number, right? and if it was already an even number followed by a 5 and nothing else following the 5, you would leave it alone as a "1" and just drop the five, right??
12.652 -> 12.65
19.9743 -> 19.97
4.32156 -> 4.322
0.019807 -> 0.01981
The above look good to me.

Thanks![/QUOTE]
 
OH, so ur not supposed to count the number to the left of the decimal point, only the number to the right are considered part of the mantissa, the quantity of which is determined by the amount of sig. figs. in the characteristic? right? :)
 
mathzeroh said:
OH, so ur not supposed to count the number to the left of the decimal point, only the number to the right are considered part of the mantissa,

Yes.

the quantity of which is determined by the amount of sig. figs. in the characteristic? right? :)

I don't understand what you mean here.
 

Similar threads

Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 10 ·
Replies
10
Views
20K
  • · Replies 1 ·
Replies
1
Views
8K