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Instantaneous velocity |
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| Apr12-05, 11:31 PM | #1 |
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Instantaneous velocity
Hi,
I was wondering how to solve the instantaneous velocity for this. I have 3 points which have 5 cm between point 1 and point 2 and 9 cm between point 2 and point 3 (this is easy, i just need to grasp the concept) The question is "What is the instantaneous velocity for point 2? How would I figure this out? thanks
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| Apr12-05, 11:32 PM | #2 |
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Do you have any times?
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| Apr12-05, 11:34 PM | #3 |
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oh, yes, sorry,
the time intervals between the points are 1/40th of a second (lets say) (sorry, I forgot to post them... I kinda forgot!) |
| Apr12-05, 11:37 PM | #4 |
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Instantaneous velocity
Can you give a little background? What kind of motion is going on here, constant acceleration?
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| Apr12-05, 11:43 PM | #5 |
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it would be variable acceleration, because the consecutive distance between 1&2 is 5 and 2&3 9... so lets say that each time, the velocity increases by one.
Would I just take the velocity of 1-2 (5cm per 1/40th of a second) and 2-3 (9cm per 1/40th of a second) and find the average of them to get the instantaneous? |
| Apr12-05, 11:49 PM | #6 |
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[tex] x(t) = x_0 + v_0t + 1/2 * at^2 [/tex] We travelled x(t) = 14cm in t=0.05sec. Can you find the acceleration? Can you find the velocity at t=0.025 with this? |
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