delta G and Keq :: Urgent, test in 1 day

huan.conchito

I got these two questions i have no idea how to do (i have answers, but no soln's)
1. Given that the affinity constatn Keq for rxn A+B=AB is 5x10^6 and the concentration of free molecules at equillibrium are Afree = 1x10^-4 and B = 1x10^-8, what is the ration of AB to A at equillibrium

ans: 0.05 : 1

2. What is the Delta G for the forward reaction x <-> y.
Given
R = 1.98x10^-3 kcal/molK
T = 298K
K'eq = 7.5

(ans: -1.18kcal/mol)

Gokul43201

Read this before posting :

http://physicsforums.com/showthread.php?t=4825

QuantumMech

Use [tex]K_{eq} = \frac{[AB]}{[A][B]} [/tex]

huan.conchito

you dont understant.. its not my hw. just tell me the formula for delta g, thats all i need

GCT

[tex]K= \frac{[x]}{[A-x][B-x]} [/tex]

You should be able to find such equations in the text by yourself, the're all listed explicitly.

...since it's urgent