What Angle Does the Angular Momentum Vector Make with the Axle?

Click For Summary
The discussion centers on calculating the angle that the angular momentum vector makes with a vertical axle in a system involving two rods and masses. The user has successfully solved for the angular momentum component along the axle but struggles with determining the angle for the third part of the problem. There is a suggestion that the angular momentum may not be parallel to the axis of rotation, indicating a possible counter-clockwise rotation due to the weights of the masses. The formula L = r x p is mentioned as a potential approach to solve for the angular momentum of each mass. Ultimately, the user seeks clarification on how to accurately compute the angle based on the system's dynamics.
pixelized
Messages
7
Reaction score
0
I solved for 2 correctly but I can't figure out what to do for #3 Any help would be much appreciated. I think it might involve L = r x p , but I'm not entirely sure.

2. [1pt]
Two lightweight rods L = 20.5 cm in length are mounted perpendicular to a vertical axle and at 180° to each other (see figure below).

At the end of each rod is a m = 602 g mass. The rods are spaced h = 35.7 cm apart along the axle. The axle rotates at 28.7 rad/s such that the angular velocity vector points upward (+). What is the component of the total angular momentum along the axle?

3. What angle does the vector angular momentum make with the axle?
 

Attachments

  • dgian1124.gif
    dgian1124.gif
    2.9 KB · Views: 938
Physics news on Phys.org
Did you get 2mL^2w for part 2?

If it's only rotating about the vertical axle... then the answer in part 2 seems to be the only component so it seems to me the angle is 0.

I'm wondering if the masses are also allowed to rotate counter-clockwise (due to their weight).
 
Last edited:
yes that's what I used for part two.

I tried 0 but it was wrong. So maybe they can rotate counter clockwise. How would that work?
 
Last edited:
pixelized said:
I solved for 2 correctly but I can't figure out what to do for #3 Any help would be much appreciated. I think it might involve L = r x p , but I'm not entirely sure.
In general, the angular momentum of a body is not parallel to its axis of rotation. Find the total angular momentum about the center of mass by adding the angular momentum of each mass, which is given by \vec{L} = \vec{r}\times \vec{p}.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
67
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 25 ·
Replies
25
Views
11K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
Replies
13
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K