| Thread Closed |
Permutation Group |
Share Thread | Thread Tools |
| Apr14-05, 11:01 PM | #1 |
|
|
Permutation Group
say you have the alternating group An for some permutation group Sn. If you are given An and then 1 odd permutation, must you be able to generate all of Sn? I tried it for S3 and I multiplied all the even perms in S3 by only 1 element that wasn't in A3 and was able to generate all of S3. Does this hold for any n?
|
| Apr15-05, 03:50 AM | #2 |
|
Recognitions:
|
Yes, that is generally true.
Note that in any group multiplication on the left by an element in the group is a bijection. [tex]ax=b \iff x=a^{-1}b[/tex] Use this to prove it for the general case [itex]S_n ,n\geq 2[/itex] The case n=1 is special, since the A1=S1. |
| Apr15-05, 05:26 AM | #3 |
|
|
Alright thanks a lot galileo. I just wanted to be sure of that fact before I brought it up in my presentation that I have to give.
|
| Thread Closed |
| Thread Tools | |
Similar Threads for: Permutation Group
|
||||
| Thread | Forum | Replies | ||
| Conjugation of a permutation by a permutation in a permutation group | Calculus & Beyond Homework | 3 | ||
| Isometry sub-group of the gauge group & the center of structural group | Differential Geometry | 0 | ||
| Lorentz group, Poincaré group and conformal group | Special & General Relativity | 12 | ||
| Permutation Group Proof | Calculus & Beyond Homework | 5 | ||
| group theory: point group of a cube | Linear & Abstract Algebra | 2 | ||