## Permutation Group

say you have the alternating group An for some permutation group Sn. If you are given An and then 1 odd permutation, must you be able to generate all of Sn? I tried it for S3 and I multiplied all the even perms in S3 by only 1 element that wasn't in A3 and was able to generate all of S3. Does this hold for any n?
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 Recognitions: Homework Help Science Advisor Yes, that is generally true. Note that in any group multiplication on the left by an element in the group is a bijection. $$ax=b \iff x=a^{-1}b$$ Use this to prove it for the general case $S_n ,n\geq 2$ The case n=1 is special, since the A1=S1.
 Alright thanks a lot galileo. I just wanted to be sure of that fact before I brought it up in my presentation that I have to give.
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