Troubleshooting: How to Calculate Bucket Speed with 118W Power Output

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Homework Help Overview

The problem involves calculating the speed of a bucket being lifted out of a well with a power output of 118W. The mass of the bucket is given as 4.5 kg, and the weight of the rope is ignored. Participants are exploring the relationship between power, force, and velocity in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss using the formula P = Fv to relate power to force and velocity, questioning the assumptions about constant velocity and the role of gravitational force. There are attempts to clarify the relationship between work, power, and energy changes in the system.

Discussion Status

The discussion is ongoing, with participants providing various insights and questioning the original poster's calculations. Some guidance has been offered regarding the need to consider both potential and kinetic energy in the problem. There is no explicit consensus, and multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the urgency of the situation, as the original poster has a deadline approaching. There is also mention of the need to clarify the conditions under which the calculations are valid, particularly regarding constant velocity.

alisa7217
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This problem is simple and i can't figure out what I am doing wrong. I am supposed to find the speed of a bucket that is being lifted out of a well with a power output of 118W. The mass of the bucket is 4.5 kg and the weight of the rope is ignore. Dividing the power by the force should give me the velocity but it doesnt. I used 118 over 4.5*9.81 and the answer is wrong. Can anyone tell me what i am doing wrong?
 
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alisa7217 said:
This problem is simple and i can't figure out what I am doing wrong. I am supposed to find the speed of a bucket that is being lifted out of a well with a power output of 118W. The mass of the bucket is 4.5 kg and the weight of the rope is ignore. Dividing the power by the force should give me the velocity but it doesnt. I used 118 over 4.5*9.81 and the answer is wrong. Can anyone tell me what i am doing wrong?
Power = work/time
work = fdcos(angle)
 
I don't have the time so i am using P=fd/t=F(d/t)=Fv which is p/f=V. The force should be m*a and a should = gravity right?
 
Yes, that looks right. :smile:
 
but the answer is wrong when i submit it...
 
alisa7217 said:
I don't have the time so i am using P=fd/t=F(d/t)=Fv which is p/f=V. The force should be m*a and a should = gravity right?
Wait a minute...
how did U get from P=W/t to P=fd/t? :confused:
 
You can also use
[tex]Work = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2[/tex]
 
Part of the work being done by the power source is increasing the potential energy of the bucket, and part is increasing the kinetic energy. You need to consider both.
 
It's asking for the FINAL velocity, right? The velocity can't be constant.
Use W=Fd and the change in kinetic energy formula.
 
  • #10
Alisa,

Your original statement is correct, and so is your calculation if the system has achieved a state of constant velocity and constant force. What is the form of the answer you are supposed to get? Perhaps the problem is not so easy and you are supposed to be looking at something other than the constant velocity condition.
 
  • #11
I still haven't figure it out and its due it 10 minutes
 
  • #12
Then believe in what you did and try to defend it until you understand what (if anything) you did wrong.
 

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