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Prove D U D' is bounded |
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| Apr19-05, 11:43 PM | #1 |
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Prove D U D' is bounded
The homework question is this:
Prove If D is a bounded subset of R then D bar = D U D’ is also bounded where D’ is the set of accumulation points of D. What is a general outline of a proof? |
| Apr20-05, 12:34 AM | #2 |
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It suffices to show that D' is bounded, as the union of 2 bounded sets is bounded.
If D is bounded, then it is contained in some finite interval, ( - N, N ). If D' is not bounded, then we can find an element, x, of D' outside of ( -N, N ), and taking a suitable neighborhood around x ( of radius less than |x| - N ), we see that it is disjoint from D ( as it is disjoint from ( -N, N ) ). Therefore, x is not an accumulation point of D. Contradiction |
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