What is the force of wind resistance on a sign attached to a vehicle?

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SUMMARY

The force of wind resistance on a sign attached to a vehicle can be calculated using the formula D = 1/2 * C_D * r * v^2 * A. In this discussion, the area (A) of the sign is 42.672 m², the vehicle's velocity (v) is 35.7632 m/s, air density (r) is 1.229 kg/m³, and the drag coefficient (C_D) is 1.28. The initial calculation yielded a force of 42929 N (9651 lbs), which is significantly higher than the expected range of 150 to 200 lbs, indicating a potential error in the calculations.

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Taiki_Kazuma
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Okay, so here's the thing...

[tex]D=\frac{1}{2}*C_D*r*v^2*A[/tex]

I need to find the Force pushing against a sign that is attached to a vehicle.

The area (A) of the sign is 60"X28" which is 42.672 [tex]m^2[/tex]

The velocity (v) that the vehicle will be moving is roughly 80 miles per hour which converts to 35.7632 [tex]\frac{m}{s}[/tex]

The next 2 I'm not sure about...

Air density (r) is 1.229 [tex]\frac{Kg}{m^3}[/tex]?
and
[tex]C_D[/tex] (Coefficeitn of friction) of this sign (which the broad side will be hitting the wind head on) is 1.28?

So I did all this calculation and got

42929 N which is 9651 lbs. That is a hell of a lot of force. I was wondering if I did all this correct...please let me know. Thanks
 
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Taiki_Kazuma said:
The area (A) of the sign is 60"X28" which is 42.672 m[tex]^2[/tex]
There's your error.
 
I would expect it to be in the 150 to 200 lb range.
 

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