- #1
VantagePoint72
- 820
- 34
Can you figure out how to read this equation as a limerick?
[tex]\int_{1}^{\sqrt[3]{3}}t^2\ dt\cdot\cos\left(\frac{3\pi}{9}\right)=\ln \sqrt[3]{e}[/tex]
Answer (in white, select to read):
Integral t-squared dt
From 1 to the cube root of 3
Times the cosine
Of 3 pi over 9
Equals log of the cube root of e
(It's true too)
[tex]\int_{1}^{\sqrt[3]{3}}t^2\ dt\cdot\cos\left(\frac{3\pi}{9}\right)=\ln \sqrt[3]{e}[/tex]
Answer (in white, select to read):
Integral t-squared dt
From 1 to the cube root of 3
Times the cosine
Of 3 pi over 9
Equals log of the cube root of e
(It's true too)
Last edited:
