Why Can't I Solve This Simple Trig Equation?

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SUMMARY

The discussion centers on solving the trigonometric equation 1 + cos(θ) = 2sin(θ). The recommended approach involves several steps: squaring both sides, substituting sin²(θ) with 1 - cos²(θ), letting x = cos(θ), solving the resulting quadratic equation, and checking each candidate solution against the original equation. This method ensures all potential solutions for θ are accurately determined and verified.

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for some reason i can't figure out how to solve this very simple trig equation.
[tex]1 + \cos{\theta} = 2\sin{\theta}[/tex] i need this so that i can solve something else. ANY IDEAS WOULD HELP ME OUT.

normally i can solve things like this but for some reason tonight i can't see what to do. to make matters worse this is due in the morning at 9am!
 
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RadiationX said:
for some reason i can't figure out how to solve this very simple trig equation.
[tex]1 + \cos{\theta} = 2\sin{\theta}[/tex] i need this so that i can solve something else. ANY IDEAS WOULD HELP ME OUT.

normally i can solve things like this but for some reason tonight i can't see what to do. to make matters worse this is due in the morning at 9am!
a) Square both sides.
b) Sub {1 - cos2(θ)} for sin2(θ).
c) Sub {x = cos(θ)}.
d) Solve quadratic.
e) Determine all candidate "θ" solutions.
f) CHECK EACH candidate "θ" solution with ORIGINAL EQUATION.


~~
 


I'm sorry to hear that you are having trouble with this trig equation. It can be frustrating when we encounter difficulties in solving problems, especially when there is a deadline looming. Have you tried breaking down the equation into smaller parts and using identities or properties of trigonometric functions to simplify it? Additionally, have you checked your calculations and made sure you are using the correct formulas? Sometimes a simple mistake can lead to a lot of confusion. If you are still stuck, perhaps reaching out to a classmate or your professor for help might be beneficial. Don't be afraid to ask for assistance, as it shows determination and a willingness to learn. I wish you the best of luck in solving this equation and completing your assignment on time. Keep pushing forward and don't give up!
 

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