How do you find to torque if force is applied over entire levl

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Homework Help Overview

The discussion revolves around calculating the torque exerted by water on a rectangular hatch in a box filled with water. Participants explore the relationship between pressure, force, and torque in the context of fluid mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of total force exerted by water on the hatch, noting that pressure varies with depth and suggesting the need for integration over the surface. Questions arise regarding the choice of the rotation axis for torque calculations.

Discussion Status

Some participants have provided insights into the integration process for determining total force and have begun to explore how to calculate torque based on that force. There is an ongoing exploration of different methods and considerations for the torque calculation.

Contextual Notes

Participants are considering the implications of varying pressure across the hatch surface and the choice of pivot point for torque calculations. The discussion includes hints about expressing area elements for integration but does not resolve the overall approach to finding torque.

bjon-07
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Lets say you have a box that is filled with water. One of the side of the box contains retangular hatch. How much torques does the water exert on the hatch?


Do you just calculate the total force that the water is exerting on the square are of the rectangular hatch. Force=Pressure X Area ?
 
Last edited:
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bjon-07 said:
Lets say you have a box that is filled with water. One of the side of the box contains retangular hatch. How much torques does the water exert on the hatch?


Do you just calculate the total force that the water is exerting on the square are of the rectangular hatch. Force=Pressure X Area ?

Pressure depends on depth, so the force is not uniform. You well have to integrate over the surface, breaking it up into strips of constant force at constant depth. I assume you want the torque calculated about the top or the bottom of the hatch. The answer depends on the rotation axis you choose.
 
I found the total force that a fluid will expert on a wall using intergration,


since force is equal to pressure X times area and pressures = density x gravity x height = interal of PGH dh


which turned out to be 1/2(density)(gravity)(width of the wall)(height of the wall)^2

now that I have the total force exerted on the object, is there a way to find the total toruqe exerted on the object. Let's make the hing of the box be the folcrum
 
bjon-07 said:
I found the total force that a fluid will expert on a wall using intergration,


since force is equal to pressure X times area and pressures = density x gravity x height = interal of PGH dh


which turned out to be 1/2(density)(gravity)(width of the wall)(height of the wall)^2

now that I have the total force exerted on the object, is there a way to find the total toruqe exerted on the object. Let's make the hing of the box be the folcrum
HINT:
Since fluid pressure ⊥ Hatch Surface:

[tex]1: \ \ \ \ \textsf{Torque} \ \, = \, \ \int_{Hatch} r \, P \ dA[/tex]

where "r" is the distance of Area Element "dA" from the Reference Point or Axis, and "P" is the fluid pressure on Area Element "dA". Both "r"and "P" will be functions of Area Element "dA" position on the Hatch Surface. You'll likely express "dA" in terms of thin rectangular area elements over the Hatch Surface.


~~
 
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