Angular momentum eigenstates and total mom. S?

[qqchico]

My problem is with finding total angular momentum S of a spin 2 particles. My quantum book doesn't do any examples with spin 2 particles do i just do
J(J+1)|j,m> and just plug in j and that will be my value.

 

[cmscoby]

Assuming zero orbital angular momentum, L = 0, then the eigenvalue of the total angular momentum squared is just S^2 = s(s+1)*(h-bar)^2, with s = 2.

Generally, the treatment of the problem is the same as with spin-1/2 particles, so the orbital- and spin-components of angular momentum add together as usual in the case of non-zero orbital angular momentum, ie j goes between abs(l - s) and abs(l+s) in integer steps, then l(l+1)*(h-bar)^2 is the eigenvalue of L^2.

Cheyne

 

[thepatientmental]

Yes, you are correct in your approach. The total angular momentum of a spin 2 particle can be calculated using the formula J(J+1)|j,m>, where J is the spin quantum number and m is the magnetic quantum number. You can simply plug in the appropriate value for J and calculate the total angular momentum. However, it is important to note that the value of J for a spin 2 particle can range from 0 to 2, so you will need to determine the specific value of J for your particle in order to accurately calculate the total angular momentum. Additionally, it may be helpful to consult other sources or textbooks for examples of spin 2 particles to gain a better understanding of the concept.