How to take a complex conjugate of a 5*5 matrices?

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SUMMARY

The discussion focuses on calculating the complex conjugate of a 5x5 matrix related to a spin-2 particle, specifically the expression . Participants clarify that to obtain the complex conjugate of a matrix, each element must be replaced with its complex conjugate without altering their positions. It is emphasized that represents a scalar (1x1 matrix) rather than a 5x5 matrix. The notation \langle\psi_{i}|\hat{S}_{z}|\psi_{j}\rangle indicates that the entries of the matrix are complex numbers unless the vectors |\psi_{i}\rangle are eigenvectors of the self-adjoint operator \hat{S}_{z>.

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I'm doing a take home final and wanted reassurance that I'm doing the problem right. the question involves taking <Sz>of |psi>. I know it's
<psi|Sz|psi>. I've never done it for a spin 2 particle which is a 5*5 matrix.Do i just take the complex conjugate of the values without switching their position within the matrices.
 
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Ok, I don't really know what your notation means, but for any matrix, yeah, you just replace each element with its complex conjugate.
 
"<psi|Sz|psi>" is not a 5*5 matrix,is just a number=matrix 1*1.If you mean

[tex]\langle\psi_{i}|\hat{S}_{z}|\psi_{j}\rangle \ , \ i,j=\overline{1,5}[/tex]

,then yes,it's a complex matrix;unless [itex]|\psi_{i}\rangle[/itex] are eigenvectors of the selfadjoint operator [itex]\hat{S}_{z}[/itex],the entries in the matrix are complex #-s with nonzero imaginary part.

Daniel.
 

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