What is the total length of an ellipse and how can it be calculated?

In summary, the total length of the ellipse x = a sin x and y = b cos x, where a>b>0, can be represented as L = 4a \int_{0}^{\pi/2} \sqrt{1-e^2sin^2x} dx, where e is the eccentricity of the ellipse (e = c/a, where c = \sqrt{a^2-b^2}). To solve this problem, one can use the parametrization of the ellipse in polar coordinates and the definition
  • #1
ktpr2
192
0
I'm asked to show that the total length of the ellipse
x = a sin x
y = b cos x, a>b>0 is

[tex] L = 4a \int_{1}^{pi/2} \sqrt{1-e^2sin^2x} dx
[/tex]
where e is the eccentricity of the ellipse (e = c/a, where c = [tex]\sqrt{a^2-b^2}[/tex]

I've tried a whole bunch of algebraic and trignometric manipulation but I'm getting the feeling I'm overlooking something. How would you approach this problem? I've tried working backwards and eventually got something of the form:

[tex] L = \int_{1}^{pi/2} \sqrt{2b^2cos^2x+c^2cos^2x-b^2(cos 2x)} dx
[/tex]

but i figured I should post here for ideas as well.
 
Physics news on Phys.org
  • #2
HINT:The total length is 4 times the arc in the first quadrant.Choose the wise parametrization and use the definition of the eccentricity (the modulus of the elliptic integral).

Daniel.
 
  • #3
This can be a challenging problem. Checking out how http://home.att.net/~numericana/answer/ellipse.htm#elliptic [Broken] have solved this might give you some ideas on how to approach it.
 
Last edited by a moderator:
  • #4
There's no big deal,Bob

[tex] L_{\mbox{ellipse}}=4L_{\mbox{arc in the first quadrant}} [/tex] (1)

Parametrization (polar elliptical)

[tex] \left\{\begin{array}{c}x(\phi)=a\cos\phi \\ y(\phi)=b\sin\phi \end{array} \right [/tex] (2)

[tex] \left\{\begin{array}{c} (dx)^{2}(\phi)=a^{2}\sin^{2}\phi \ (d\phi)^{2}\\ (dy)^{2}(\phi)=b^{2}\cos^{2}\phi \ (d\phi) ^{2}\end{array} \right [/tex] (3)

[tex] L_{\mbox{arc in the first quadrant}} =\int \sqrt{(dx)^{2}+(dy)^{2}} =\int_{0}^{\frac{\pi}{2}} \sqrt{a^{2}\sin^{2}\phi+b^{2}\cos^{2}\phi} \ d\phi [/tex] (4)

Now i'll leave it to the OP to finish it.

Daniel.

P.S.His answer is wrong.
 
  • #5
wow. that was down and funky. I figured it out in four lines after an embarrassing number of scrap sheets before. Thanks people.

I'll give several hints to those with the same question in the future:

The integral is from 0 to 2pi originally, but you can cut it down to 0 to pi/2 and multiply by four. recall that c^2is really just 1 - b^2/a^2 and when at the end of a deserted road, question if you can multiply by 1 expressed in a twisty way.
 
  • #6
the length of any geometrical arc is given by [ intg of ( (dx .dx +dy.dy)^1/2 ) ] within proper limits... that is according to "pythogorean theorem"..

on simplifying the above thing we get... intg [(1+(dy/dx)^2)^1/2) ].dx

Now, comming to the problem i.e., length of an ellipse, calculate (dy/dx) from the standard equation in terms of "x" and put it in the above integral and solve thus obtained integral within proper limits...thas alll... :)

if u do tht u will get approx L= pi[ 3(a+b)- {(3a+b)(a+3b)}^1/2 ]
 
  • #7
By "within limits" i mean the limits of corresponding variable by which the integrand is multiplied i.e. the factor by which the integrand is multiplied which is a differential magnitude... ( eg., limits of "x" if the integrand is multiplied by "dx" and limits of "theta" if the integrand is multiplied by "d(theta)" )
 

What is the total length of an ellipse?

The total length of an ellipse is the distance around the entire perimeter of the shape.

How is the total length of an ellipse calculated?

The total length of an ellipse can be calculated using the following formula: L = π(3(a + b) - √(3a + b)(a + 3b)), where a and b are the lengths of the semi-major and semi-minor axes, respectively.

Is the total length of an ellipse different from its perimeter?

No, the total length of an ellipse is the same as its perimeter.

Does the total length of an ellipse change if the axes are rotated?

No, the total length of an ellipse remains the same regardless of the orientation of its axes.

Can the total length of an ellipse be infinite?

No, the total length of an ellipse is a finite value and cannot be infinite.

Similar threads

  • Introductory Physics Homework Help
Replies
28
Views
221
  • Introductory Physics Homework Help
Replies
8
Views
477
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
1K
Replies
3
Views
1K
  • Astronomy and Astrophysics
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
17
Views
224
  • Introductory Physics Homework Help
Replies
7
Views
612
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
Back
Top