What Is the Net Charge of a Gold Nugget After Removing 1% of Its Electrons?

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SUMMARY

A 1.16 g nugget of pure gold, with an atomic number of 79, has a net charge of 0. When 1% of its electrons are removed, the net charge becomes positive due to the loss of negatively charged electrons. To calculate the number of electrons in the nugget, one must convert the mass to moles using Avogadro's number (6.022 x 1023 atoms/mole) and then determine 1% of the total electron count. The charge of the removed electrons is calculated using the elementary charge of 1.602 x 10-19 coulombs.

PREREQUISITES
  • Understanding of Avogadro's number (6.022 x 1023 atoms/mole)
  • Familiarity with the concept of atomic number and electron count
  • Basic knowledge of electric charge (1.602 x 10-19 coulombs)
  • Ability to perform mole-to-gram conversions
NEXT STEPS
  • Calculate the total number of electrons in a 1.16 g gold nugget
  • Learn how to convert mass to moles using Avogadro's number
  • Understand the implications of electron removal on net charge
  • Explore the concept of valence electrons versus total electrons
USEFUL FOR

Students studying chemistry, physicists interested in atomic structure, and educators teaching concepts of charge and atomic theory.

pwise2682
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1.16 g nugget of pure gold has a net charge of 0. What would be its net charge after it has 1% of its electrons removed?

I'm assuming you may have to convert it to moles use avogadros number, use the electrical charge of 1.602E -19 and mulitply the answer by .01 but i can't get an answer
 
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How many electrons does that many moles have. How many electrons is 1%? Whats the charge of that 1%?
 
The atomic number of gold is 79, which means each atom has 79 electrons.

Now the problem states 1% of electrons, not 1% of valence electrons, which is a smaller population.
 

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