Proving 1 = -1: Help and Discussion

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Discussion Overview

The discussion revolves around a claim that 1 equals -1, stemming from a manipulation of square roots involving complex numbers. Participants explore the validity of the mathematical steps taken and the implications of complex number properties.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant claims that 1 equals -1 by manipulating square roots, suggesting that sqrt(1) equals sqrt(-1*-1) equals i^2.
  • Another participant points out a mistake in the second step, emphasizing the need to consider the full definition of the square root function.
  • A participant asserts that the square root function always returns a non-negative real value, indicating that sqrt(ab) equals sqrt(|a|)sqrt(|b|) only when ab is non-negative.
  • Another participant states that sqrt(-1 * -1) does not equal sqrt(-1) * sqrt(-1), reinforcing the error in the original claim.
  • One participant compares the erroneous step to the incorrect assertion that |1| equals |-1|, leading to the conclusion that 1 equals -1.
  • A later reply discusses the ordering of complex numbers, explaining that defining i as sqrt(-1) leads to ambiguity between i and -i due to the lack of order in complex numbers.
  • Another participant notes that the equality (ab)^(1/2) equals a^(1/2)*b^(1/2) holds only if at least one of a or b is non-negative, suggesting a conditionality in the manipulation of square roots.

Areas of Agreement / Disagreement

Participants generally disagree on the validity of the original claim that 1 equals -1, with multiple competing views regarding the properties of square roots and complex numbers. No consensus is reached.

Contextual Notes

Participants highlight limitations in the manipulation of square roots, particularly regarding the assumptions about the signs of the numbers involved and the properties of complex numbers.

IsotropicSpinManifol
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Ok
This is my first post HI everyone!

Whats wrong with this.

1 = sqrt(1) = sqrt (-1*-1) = sqrt(-1)*sqrt(-1) = i * i = i^2 = -1

therefore

1 = -1

0= -2,2

0 = Real Number Set

etc

Dammit I am right! And everyone in the history of maths is wrong!

AHHAHAHAA

ahum
 
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Holy ****! You've gotten us! :rolleyes:

You're mistake is in the second step, you need to consider the full definition, parameter-usage and application of the square root function before splitting it up like that.
 
Simply put:Sqrt always returns a real positive value.

[tex]\sqrt{ab}=\sqrt{|a|}\sqrt{|b|}[/tex] , [tex]ab\geq0[/tex].

Daniel.
 
[itex]\sqrt{-1 \cdot -1}\not=\sqrt{-1}\cdot \sqrt{-1}[/itex].
 
Same thing but a bit more obvious, your step is like saying:

[tex]|1| = |-1|[/tex]

Therefore:

[tex]1 = -1[/tex]
 
What everyone else has said is true. And it is basically due to the fact that the complex numbers cannot be ordered. If we define i by "[tex]i= \sqrt{-1}[/tex] or even i2= -1, we cannot distinguish between "i" and "-i". (Since the complex numbers are not ordered, we can't say "the positive root" and "the negative root".)

More precise is to define the complex numbers as pairs of real numbers (a, b) and define addition by (a,b)+ (c,d)= (a+c, b+d) and multiplication by (a,b)(c,d)= (ac-bd, ad+ bc). (Then a+ bi is just a notation for (a,b).) Using that notation this problem disappears.
 
(ab)^1/2 = a^1/2*b^1/2 if and only if ATLEAST one of a, b is Non negative. If a and b are both non negative then (ab)^1/2 = - (a)^1/2*(b)1/2 ;) cheers!
 

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