.Calculating Heat Released from Gas Expansion at Constant Temperature

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SUMMARY

The discussion focuses on calculating the heat released from an ideal gas during an isothermal expansion process. The gas transitions from an initial state at pressure Po, volume Vo, and temperature To to a state at temperature 2To, then returns to the original state. The internal energy increases by 3PoVo/2 during the transition from point B to To, but since the process is isothermal, the heat released from point B to To is definitively 0. This conclusion is based on the principle that internal energy changes only with temperature variations, which do not occur in this scenario.

PREREQUISITES
  • Understanding of ideal gas laws
  • Knowledge of thermodynamic processes, specifically isothermal processes
  • Familiarity with internal energy concepts in thermodynamics
  • Basic mathematical skills for calculating pressure, volume, and temperature relationships
NEXT STEPS
  • Study the principles of isothermal processes in thermodynamics
  • Learn about the ideal gas law and its applications
  • Explore the relationship between internal energy and temperature changes
  • Investigate other thermodynamic processes such as adiabatic and isochoric processes
USEFUL FOR

This discussion is beneficial for students and professionals in physics, particularly those studying thermodynamics, as well as engineers and scientists working with gas systems and heat transfer.

pkossak
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An ideal gas at pressure, volume, and temp, Po, Vo, and To, respectively, is heated to point A, allowed to expand to point B also at A's temperature 2To, and then returned to the original condition. The internal energy increases by 3PoVo/2 going from point B to point To. How much heat left the gas from point B to point To?

a. 0 b. PoVo/2 c. 3PoVo/2 d. 5PoVo/2

http://www.msu.edu/~kossakze/pvt.gif

Not sure about this one. Any suggestions? Thanks
 
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Can't understand how internal energy increases if the temp. changes from 2T0 to T0??
 


The correct answer is a. 0. This is because the process described is an isothermal expansion, meaning the temperature remains constant throughout. In an isothermal process, the change in internal energy is equal to 0, so no heat would be released or absorbed by the gas. The internal energy only increases when the temperature changes, which does not occur in this scenario. Therefore, the correct answer is 0.
 

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