How Do You Calculate Mass and Spring Constant from Oscillation Period Changes?

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Homework Help Overview

The problem involves determining an unknown mass and spring constant from changes in the period of oscillation when an additional mass is added. The context is rooted in oscillatory motion and the relationship between mass, spring constant, and period.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply the formula for the period of oscillation but struggles with the two-variable nature of the problem. Some participants suggest squaring both sides of an equation to isolate variables, while others clarify the algebraic steps involved.

Discussion Status

The discussion is active, with participants providing guidance on algebraic manipulation and encouraging the original poster to continue working through the equations. There is no explicit consensus on the final solution, but a productive direction is being explored.

Contextual Notes

The problem involves two unknowns, which complicates the resolution. The original poster expresses difficulty in handling the algebraic relationships between the variables.

izmeh
In a lab write up, i am given the following problem.

An unkown mass M is found to have a period of oscillation of 1 second using a spring of unkown spring constant K. When 200gms were added to the initial mass, the period of oscillation increased by 0.6 seconds. Determin the unkwon mass M(gms) and the Spring Constant K(N/m).

I am not very good at working with problems that have 2 variables. I have come up with a formula however.

T=2pi(sq.rt[M/K])
1 = 2pi(sq.rt[M/K])
1.6 = 2pi(sq.rt[m+.2]/K]
1/1.6 = sq.rt[m/m+.2]

however, i can not for the life of me figure out how to get the answer for M for this.

Is anyone willing to help me?
 
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square both sides & solve for m
 
m cancels out
 
Try it again. It doesn't cancel out.

You're now starting from this line right?
1/1.6 = sq.rt[m/m+.2]
How can m cancel out? When you square it, the right side becomes m/(m+.2).

(If you still can't get it, post what you're doing so we can find the error.)
 
.625² = sq.rt[m/m+.2]
.391 = m/m+0.2
.391(m+.2) = M
.391m + .078 = m

and so on...
 
Yes, so?

Now you have a simple linear equation for m. There's no way that m cancels out. Finish it & you'll have your solution.
 

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