Determine Max Speed for a Pickup Truck

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    Max Speed Truck
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Homework Help Overview

The problem involves determining the maximum speed at which a pickup truck can negotiate a curve without a crate of eggs sliding off the flatbed. The context includes concepts of circular motion and friction, with specific parameters such as the radius of the curve and the coefficient of static friction provided.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between centripetal acceleration and frictional force, with one participant attempting to derive the maximum speed using the formula for centripetal acceleration and the coefficient of friction.

Discussion Status

The discussion includes attempts to clarify the problem and explore the necessary calculations. Some participants provide guidance on how to approach the problem, while others remind that solutions should not be posted directly. There is a focus on understanding the underlying physics rather than arriving at a final answer.

Contextual Notes

There is a mention of forum policies regarding homework help, indicating that participants are encouraged to guide understanding rather than provide complete solutions.

PhysicsDud
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I'm having a real problem trying to work out this question:

A crate of eggs is located in the middle of the flatbed of a pickup truck. The truck is negotiating a curve in the road that may be considered as an arc of a circle of radius 35 m. if the coefficient of static friction between the flatbed and the crate is 0.66, with what maximum speed the truck can negotiate the curve if the crate is not to slide out during cornering?

Can anyone help me?

Thanks,
PhysicsDud :eek:
 
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Hi, just letting you know that if this is homework, there is a special section in this forum for this: https://www.physicsforums.com/forumdisplay.php?f=35
 
Last edited by a moderator:
I'll help you start off. Since the truck is making a uniform circular potion, the centripetal acceleration is v²/r, meaning the road exerts a force mv²/r on the truck. This triggers the static friction force between the flatbed and the crate.
 
a(c) = v^2/r = v^2/35

You want to find the maximum 'acceleration' your friction can give you, and set it equal to that centripetal acceleration to find the corresponding velocity.

Mu=Friction Force/Normal Force
Mu*Fn=Ff
Mu*m*g=m*a(friction)
.66*g=a(friction)

Now back to original.

v^2/35=.66*g
v=15 m/s
 
HiPPiE said:
a(c) = v^2/r = v^2/35

You want to find the maximum 'acceleration' your friction can give you, and set it equal to that centripetal acceleration to find the corresponding velocity.

Mu=Friction Force/Normal Force
Mu*Fn=Ff
Mu*m*g=m*a(friction)
.66*g=a(friction)

Now back to original.

v^2/35=.66*g
v=15 m/s

Read the policies of the site, do not post solutions.

Regards,

Nenad
 

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