Integrating a second derivative-involving solution for Simple Harmonic Motion

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Homework Help Overview

The discussion revolves around integrating the equation of motion for simple harmonic motion, specifically the second derivative of position with respect to time, represented as m(d²x/dt²) = -kx. Participants are exploring the integration process to derive the general solution, x = Acos(wt + c).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to integrate the second derivative but encounters difficulties with the separation of variables and the integration process. Some participants suggest rearranging the second derivative into a form involving velocity, while others question how to handle the resulting expressions after integration, particularly concerning constants and the relationship between v and x.

Discussion Status

Participants are actively engaging with the problem, offering hints and alternative approaches. There is a recognition of the need for further integration to reach the general solution, and some guidance has been provided regarding the use of initial conditions and rewriting equations.

Contextual Notes

There is an ongoing discussion about the implications of initial conditions on the integration constant and the challenges posed by the negative k/m term in the equations being manipulated.

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Hello, i am now in the process of integrating m(d^2x/dt^2)=-kx which i know i will have to do twice in order to obtain the general solution to simple harmonic motion, x= Acos(wt+c) c=phi

but I'm just having problems with the second derivative of acceleration (d^2*x/dt^2) when it comes to integrating, I tried separating them into dv/dt and then dv/dx and dx/dt, so i obtain v, etc... but this complicates things even more for me! It would be so great if someone could give me a hint as to where i can start in integrating with this second derivative...
Thank you very much for your time.
 
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insertnamehere said:
Hello, i am now in the process of integrating m(d^2x/dt^2)=-kx which i know i will have to do twice in order to obtain the general solution to simple harmonic motion, x= Acos(wt+c) c=phi

but I'm just having problems with the second derivative of acceleration (d^2*x/dt^2) when it comes to integrating, I tried separating them into dv/dt and then dv/dx and dx/dt, so i obtain v, etc... but this complicates things even more for me! It would be so great if someone could give me a hint as to where i can start in integrating with this second derivative...
Thank you very much for your time.
The 2nd differential is often rearranged like this,

[tex]\frac{d^2x}{dt^2}= v\frac{dv}{dx}[/tex]

and you get that this way,

[tex]\frac{d^2x}{dt^2}=\frac{d}{dt}(dx/dt)=\frac{dv}{dt} = \frac{dv}{dx}\frac{dx}{dt}= \frac{dv}{dx}v = v\frac{dv}{dx}[/tex]

substitute for [tex]\frac{d^2x}{dt^2}[/tex] to [tex]v\frac{dv}{dx}[/tex] then do the integration.
 
Yes, i tried doing that, but then eventually i get stuck with
(v^2)/2= (-k/m)(x^2)/2 + C
Would i have to integrate again to obtain the general solution of
x=Acos(wt+c)? What can i do with the v^2 and the x^2, and the negative k/m?
 
Your halfway there.
From the initial conditions of the problem, work out a value for C.
rewrite the eqn as v = whatever ...
convert v to dx/dt and integrate agan.
 

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