Intersection points of the graph its solutions?

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Homework Help Overview

The discussion revolves around finding the intersection points of the functions f(theta) = 2sin(theta) - 1 and g(theta) = 3cos(theta) + 2, and understanding the implications of these intersection points in terms of solutions or zeros of a function.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify what is meant by finding intersection points and how these relate to zeros of a function. There are questions about the process of graphing to find intersections and the significance of these points as solutions.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the relationship between intersection points and zeros, as well as the method of graphing to find these points. Some guidance has been offered regarding solving the equations simultaneously to find angles, but clarity is still needed on the overall concept.

Contextual Notes

Participants are navigating the definitions and relationships between the functions in polar form and their intersection points, indicating a need for further exploration of these concepts.

yourmom98
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The graphs of f(theta) = 2sin(theta) - 1 , and g(theta) = 3cos(theta)+2 are given.
What equation would have the intersection points of the graph its solutions?


ummm... what does this mean? and how do i solve it?
 
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Find the intersection points of f(t) and g(t) and find a function that has those points as solutions (zeros).
 
i still don't understand i can find the points where f(t) and g(t) intersect by graphing (how do i do this by graphing?) but what do you mean by having same points as zeros?
 
Both of these are the equations of graphs in their polar form.These graph would intersect at some particular point whose position vector will make some THETA angle with the x-axis.To find this particular THETA , solve the above two equations simultaneusly by equation f(Q) and g(Q) and then finding the angle(s).

BJ
 

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