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Force due to pressure on side of a container 
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#1
Sep505, 03:42 PM

P: 17

Hi gang,
I'm having an issue with one my homework problems. There is an L shaped tank, 3d in height, 1d in width. The verticle part of the L is 2d in height, and the horizontal part of the L is a 1d box. d = 8m _    _ _ _<Force due to pressure needed for this side. I need to find the pressure on the right wall of the horizontal part of the L. What I have managed to get so far is the equation: F=(rho)(g)(width)(height^2) Not very far, I know. I'm assuming I have to integrate this somehow, but I am unsure as to how to set it up. I'm not really looking for a solution, just a push in the right direction with regards to the integration, or in the correct direction if I am very, very wrong. Thanks, in advance, for the help. 


#2
Sep505, 03:57 PM

HW Helper
P: 876




#3
Sep505, 03:59 PM

P: 17

From the side, sorry.



#4
Sep505, 04:00 PM

HW Helper
P: 876

Force due to pressure on side of a container
Ok, hang on a min.



#5
Sep505, 04:00 PM

PF Gold
P: 864




#6
Sep505, 04:07 PM

P: 17

We are actually using gauge pressure, so it simplifies the formula you gave a bit. I did get the correct answer using your method, though, so thank you very much.



#7
Sep505, 04:10 PM

HW Helper
P: 876

Arrgh, too late!!
Oh, well. What LeonhardEuler said. I enclose a small piece of work explaining how to do these types of integrals for pressure over a submerged area. It may be useful for yourself or anyone else reading these posts. 


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