What is the mass of the string?

  • Thread starter Thread starter timtng
  • Start date Start date
  • Tags Tags
    Spring
Click For Summary
SUMMARY

The mass of the string is calculated to be 0.0001 kg when the tension is 18 N and the fundamental frequency is 150 Hz. The calculations involve using the wave speed formula, where the speed (v) is determined as 600 m/s, leading to a linear density (μ) of 0.00005 kg/m. For the second part, to achieve three segments at the same frequency, the required tension is determined to be 2 N, using the relationship between wave speed, tension, and linear density.

PREREQUISITES
  • Understanding of wave mechanics and fundamental frequency
  • Familiarity with tension and linear density in strings
  • Knowledge of the wave speed formula: v = fλ
  • Ability to manipulate equations involving tension and linear density
NEXT STEPS
  • Study the relationship between tension and frequency in vibrating strings
  • Learn about harmonic frequencies and their calculations
  • Explore the effects of varying tension on wave speed in strings
  • Investigate the principles of wave mechanics in different mediums
USEFUL FOR

Physics students, educators, and anyone interested in understanding wave mechanics and string vibrations in physics.

timtng
Messages
25
Reaction score
0
When the tension is 18 N, a string 2.00 m long has a fundamental frequency of 150 Hz.
a.) What is the mass of the string?
b.) With what tension must the string be stretched so that it vibrates in three segments at 150 Hz?

This is what I came up with:
a.) f=v/2L, v=2Lf=2*2*150=600 m/s
v=sqrt(T/μ), v^2=T/μ, μ=T/v^2=18/600^2=.00005 kg/m
M=2*.00005=.0001 kg

b.) L=3λ/2, 2=3λ/2, λ=4/3
v=fλ=150*4/3=200 m/s
v^2=T/μ, T=μ*v^2=.00005*200^2=2 N

Am I working both problems correctly?

Thanks
 
Physics news on Phys.org
Your physics looks good. (I didn't check the arithmetic :wink:)
 
for your response! Your calculations for both problems seem to be correct. In part a), you correctly used the equation for the speed of a wave (v) in terms of its frequency (f) and wavelength (λ) to solve for the linear density (μ) of the string. And in part b), you correctly used the equation for the speed of a wave (v) in terms of its tension (T) and linear density (μ) to solve for the tension needed for the string to vibrate in three segments at 150 Hz. Keep up the good work!
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
4K