How Do You Integrate \(\cos^2(x) \tan^3(x) dx\)?

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SUMMARY

The integral \(\int \cos^2(x) \tan^3(x) \, dx\) can be approached using substitution and integration by parts. The transformation \(\int \frac{\sin^{3}(x)}{\cos(x)} \, dx\) simplifies the problem by breaking it down into manageable components. The integral can be expressed as \(\int \tan(x) \, dx - \int \sin(x) \, d(\sin(x))\), leading to a clearer path for evaluation. This method effectively utilizes trigonometric identities to facilitate integration.

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I'm attempting to find:
[tex]\int \cos^2x\tan^3x dx[/tex]
I've tried substitution and integration by parts but I'm having no success. Can someone help me out on how I get this one started?

Steve
 
Last edited:
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It's no big deal.

[tex]\int \frac{\sin^{3}x}{\cos x} \ dx =\int \frac{\sin x \left(1-\cos^{2}x\right)}{\cos x} \ dx =\int \tan x \ dx -\int \sin x \ d\left(\sin x\right) = ...[/tex]

Daniel.
 
Thanks dextercioby, I understand it now.

Steve
 

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