How Do You Balance Complex Redox Equations with Multiple Oxidation Changes?

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SUMMARY

The discussion focuses on balancing complex redox equations, specifically the reaction involving chromium triiodide (CrI3), potassium hydroxide (KOH), and chlorine (Cl2). Participants identified oxidation numbers, noting that chromium (Cr) transitions from +3 to +6, iodine (I) from -1 to +7, and chlorine (Cl) from 0 to +1. The recommended approach involves breaking the reaction into half-cells, balancing exotic elements first, and then applying standard half-cell balancing techniques to ensure charge and atom conservation.

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dajugganaut
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hi all, my chemistry assignment had a bunch of questions on redox equations balancing. i got stuck on this one:

[tex]\CrI_{3} + KOH + \Cl_{2} \rightarrow \K_{2}CrO_{4} + \KIO_{4} + KCl + \H_{2}O [\tex]<br /> <br /> so far, i tried to find ON numbers of the various elements.<br /> Cr changes from +3 to +6<br /> I changes from -1 to +7<br /> Cl changes from 0 to +1<br /> <br /> this means that Cr and I undergo a loss of electrons, while Cl undergoes a gain. i don't know how to solve this question when there are multiple LEO.<br /> <br /> can you help? =)<br /> <br /> [ EDIT : my attempt at LATEX has proved to be yet another disaster ][/tex]
 
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For your latex in the final tex it should be a FORWARD SLASH, not a backslash... thus the mess. Also you don't need a backslash to start off a new word. ANyway it look like this:

[tex]CrI_{3} + KOH + Cl_{2} \rightarrow K_{2}CrO_{4} + KIO_{4} + KCl + H_{2}O[/tex]

i suggest you break into half cells as follows
[tex]CrI_{3} \rightarrow K_{2}CrO_{4} + KIO_{4}[/tex]
[tex]KOH \rightarrow H_{2}O[/tex]
[tex]Cl_{2} \rightarrow KCL[/tex]

Balance everything exotic (like K, Cr, I, Cl) first. Then follow the usual steps for half cells. I know it doesn't look like it will work.. but if you balance each half cell properly in temrs of charge and atoms yu should be fine
 

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