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Annuity compounded annually |
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| Sep28-05, 07:24 AM | #1 |
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Annuity compounded annually
I am having trouble with the following problem:
What will be the value of an annuity in today's dollars if $1000 is to be deposited for 18 years into an account paying 4.5% interest compounded annually? I used the following formula (I'm guessing I've figured something incorrectly) A= P[(1 + r)^m - 1]/r P=1000 r=i/n i=4.5% or .045 n=1 t=18 m=n(t) or 18 1000[1 + .045)^18 - 1/.045 I know this is incorrect because my choices are multiple choice |
| Sep28-05, 03:22 PM | #2 |
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There are a couple of possibilities. One, your last equation either has a typo or you did it wrong:
1000[1 + .045)^18 - 1/.045 ==> should be [tex]\frac{1000[(1 + .045)^{18} - 1]}{.045}[/tex] The second is that it's not an annuity problem but rather a simple compound interest problem [tex]FV = PV(1+r)^m[/tex] |
| Sep29-05, 12:43 AM | #3 |
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Thank you very much.
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