How Is Spring Potential Energy Calculated?

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SUMMARY

The potential energy (PE) of a spring is calculated using the formula PE = 0.5 * k * x², where k is the spring constant and x is the displacement from the equilibrium position. In the discussion, a force of 800 N stretches the spring 0.200 m, resulting in a spring constant (k) of 4000 N/m. The potential energy when stretched to 0.200 m is 80.0 J, calculated as PE = 0.5 * 4000 N/m * (0.200 m)². When compressed by 5.00 cm (0.050 m), the potential energy is 5.00 J, demonstrating that potential energy is directly proportional to the square of the displacement.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with the formula for potential energy in springs
  • Basic knowledge of units of force (Newtons) and energy (Joules)
  • Ability to perform calculations involving squares and multiplication
NEXT STEPS
  • Study the derivation of Hooke's Law and its applications in physics
  • Learn about energy conservation in mechanical systems
  • Explore the effects of different spring constants on potential energy
  • Investigate real-world applications of springs in engineering and design
USEFUL FOR

Students studying physics, educators teaching mechanics, and engineers designing systems involving springs will benefit from this discussion.

erik-the-red
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A force of [tex]800 m[/tex] stretches a certain spring a distance of [tex]0.200 m[/tex].

1. What is the potential energy of the spring when it is stretched a distance of [tex]0.200 m[/tex]?

Why is the answer 80.0 J instead of 160. J?

2. What is its potential energy when it is compressed a distance of [tex]5.00 cm[/tex]?

Why is the answer 5.00 J?
 
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How does the potential energy of a spring depend on how much it is stretched or compressed?

Note that it's not saying that a force of 800 N was uniformly applied over a distance of 0.200 m; it says that a force of 800 N will stretch the spring 0.200 m. (Use that fact to find the spring constant.)
 
Thank you so much!
 

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