Congruence Classes: Solve the Hard Problem!

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SUMMARY

The discussion centers around the mathematical problem of congruence classes, specifically evaluating the expression (2^2^...^2)(n times) and its equivalence to (2^2^...^2)(n-1 times) mod n. The example provided illustrates that for n=2, the equation holds true as 4 is congruent to 2 modulo 2. Participants explore the implications of this congruence and its validity for other values of n, emphasizing the complexity of the problem.

PREREQUISITES
  • Understanding of modular arithmetic
  • Familiarity with exponentiation and its properties
  • Basic knowledge of congruence classes
  • Experience with mathematical proofs
NEXT STEPS
  • Research modular exponentiation techniques
  • Explore the properties of congruence relations
  • Study the implications of the Chinese Remainder Theorem
  • Investigate advanced topics in number theory related to exponentiation
USEFUL FOR

Mathematicians, students studying number theory, and anyone interested in advanced mathematical concepts related to congruence classes and modular arithmetic.

shaner-baner
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Here is a fun problem, it's hard to write out clearly, but I'll try to do it w/ little confusion.
Is it, or is it not true that
(2^2^...^2)(n times)=(2^2^...^2)(n-1 times) mod n
so for example, when [tex]n=2[/tex], [tex]2^2=2[/tex] ->
[tex]4=2[/tex] mod 2.
 
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He he sorry.
 
Last edited:

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