What is the equation to solve for v in this problem?

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Homework Help Overview

The discussion revolves around solving the equation \(\frac{150}{v+20}+\frac{150}{v-5}=3.5\) for the variable \(v\). Participants are exploring methods to manipulate the equation and clarify the steps involved in reaching a solution.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants suggest making the denominators the same and cross-multiplying to eliminate fractions. There are attempts to solve the resulting quadratic equation, with some expressing uncertainty about their calculations and others questioning the accuracy of previous results.

Discussion Status

The discussion is active, with participants providing different approaches and questioning each other's calculations. Some guidance has been offered regarding the manipulation of the equation, but there is no explicit consensus on the correct solution or method at this point.

Contextual Notes

There appears to be some confusion regarding the correct form of the quadratic equation derived from the original equation, with differing interpretations of the results. Participants are also checking each other's answers for accuracy.

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can some 1 give me a hand with this? thanks
[tex]\frac{150}{v+20}+\frac{150}{v-5}=3.5[/tex]
 
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1. make the denominator the same.
2. cross multiply the equation to get rid of the fraction form.
3. solve the quadratic equation.
 
i get the -65 n 80 which i think is right so thanks leong
 
check your answer !
 
80 works, -65 doesnt
 
it came down to:
[tex]3.5v^2+52.5v-650[/tex]
 
Uhmmm, I think you should check your calculation again.
Here we go:
[tex]\frac{150}{v + 20} + \frac{150}{v - 5} = 3.5[/tex]
Multiply both sides by (v + 20) (v - 5)
[tex]\Leftrightarrow (v + 20)(v - 5)\left(\frac{150}{v + 20} + \frac{150}{v - 5}\right) = 3.5(v + 20)(v - 5)[/tex]
[tex]\Leftrightarrow 150(v - 5) + 150(v + 20) = 3.5(v ^ 2 + 15v - 100)[/tex]
[tex]\Leftrightarrow 300v + 2250 = 3.5v ^ 2 + 52.5v - 350[/tex]
[tex]\Leftrightarrow ...[/tex]
Can you go from here?
By the way, it does not come down to 3.5v2 + 52.5v - 650 = 0.
Viet Dao,
 

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