Represent a matrix on the (x,y)-plane

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This discussion focuses on representing a matrix on the (x,y)-plane, specifically using a 2x2 matrix such as \left(\begin{array}{cc}2&3\\0&1\end{array}\right). The key takeaway is that a matrix can be interpreted as a linear transformation that acts on vectors in the plane. By applying the matrix to basis vectors (1,0) and (0,1), one can visualize how the transformation alters the coordinate system, effectively changing the representation of points in the (x,y)-plane.

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I'm having trouble understanding how to represent a matrix on the (x,y)-plane. It seems like my classes expect me to know this, but I was never shown how. I've heard that there are a lot of connections between matrices and geometry, that matrices can be used to provide a geometric representation of something, but I don't understand how. For example, if I have a 2x2 matrix [tex]\left(\begin{array}{cc}x&y\\0&1\end{array}\right)[/tex], how does that look in the (x,y)-plane? I really want to understand this better.
 
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hgj said:
I'm having trouble understanding how to represent a matrix on the (x,y)-plane. It seems like my classes expect me to know this, but I was never shown how. I've heard that there are a lot of connections between matrices and geometry, that matrices can be used to provide a geometric representation of something, but I don't understand how. For example, if I have a 2x2 matrix [tex]\left(\begin{array}{cc}x&y\\0&1\end{array}\right)[/tex], how does that look in the (x,y)-plane? I really want to understand this better.

Well you could look at it as two vectors.
 
I have no idea what you mean by "represent a matrix on the xy-plane".

Perhaps you mean "represent a matrix as a linear transformation on the xy-plane.

If you are going to do that, it would be better not to have "x" and "y" in the matrix itself.
If the matrix were [tex]\left(\begin{array}{cc}2&3\\0&1\end{array}\right)[/tex]
for example then we could note that multiplying the "point" (x,y) by it gives
[tex]\left(\begin{array}{cc}2&3\\0&1\end{array}\right)\left(\begin{array}{cc}x\\y\end{array}\right)= \left(\begin{array}{cc}2x+3y\\y\end{array}\right)[/tex]

You could also, perhaps more simply, apply it to the "basis" vectors (1, 0) and (0,1) and see what happens there:

[tex]\left(\begin{array}{cc}2&3\\0&1\end{array}\right)\left(\begin{array}{cc}1\\0\end{array}\right)= \left(\begin{array}{cc}2\\0\end{array}\right)[/tex]

[tex]\left(\begin{array}{cc}2&3\\0&1\end{array}\right)\left(\begin{array}{cc}0\\1\end{array}\right)= \left(\begin{array}{cc}3\\1\end{array}\right)[/tex]

Draw the lines through (0,0) and each of those and imagine them as what the matrix does to the xy-axes. Of course, all points between the xy-axes are changed into points between those lines.
 

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