factoring problem

**EvLer** · Oct3-05, 11:50 PM

How can i factor this nicely, so that i can get a form to inverse-laplace transform it

$LaTeX Code: \\frac{0.25s}{s^2+0.25s+0.25}$

so far i get this in denominator: $LaTeX Code: (s+\\frac{1}{8})^2+\\frac{15}{64}$

after completing the square, but then the last fraction is not a square of anything.... and i need a square there, the way everything else looks...

**CarlB** · Oct4-05, 01:41 AM

The denominator is already a square. I don't see how you got the other stuff. The answer should be a simple polynomial multiplied by an exponential.

Carl

**EvLer** · Oct4-05, 02:09 AM

I don't see a square there, if

this is a simple algebra thing... i guess i'm not seeing it

could you show please?

**ehild** · Oct4-05, 02:25 AM

Originally Posted by EvLer

How can i factor this nicely, so that i can get a form to inverse-laplace transform it

$LaTeX Code: \\frac{0.25s}{s^2+0.25s+0.25}$

so far i get this in denominator: $LaTeX Code: (s+\\frac{1}{8})^2+\\frac{15}{64}$

after completing the square, but then the last fraction is not a square of anything.... and i need a square there, the way everything else looks...

Do not panic. 15/64 is the square of

$LaTeX Code: \\frac{\\sqrt {15}}{8}$

ehild

**CarlB** · Oct4-05, 02:35 AM

Originally Posted by EvLer

I don't see a square there, if

this is a simple algebra thing... i guess i'm not seeing it could you show please?

My mistake. I don't see anything wrong with the way you're doing this problem, so far.

Carl