Solving Limits and Continuity Problems with Examples and Proofs

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SUMMARY

This discussion focuses on solving limits and continuity problems in calculus, specifically addressing the continuity of functions and the application of the Intermediate Value Theorem (IVT). The user seeks to determine the constant 'a' for the function g(x) = (x^2 - a^2)/(x-a) to ensure continuity at x = a, and to find the value of c in the function f(x) = x^3 - x^2 + x - 2 on the interval [0,3] guaranteed by IVT. Additionally, the discussion includes the Dirichlet function, demonstrating its discontinuity at all real numbers using the definition of continuity.

PREREQUISITES
  • Understanding of limits and continuity in calculus
  • Familiarity with the Intermediate Value Theorem (IVT)
  • Knowledge of the definition of continuity involving epsilon-delta
  • Basic algebraic manipulation of functions
NEXT STEPS
  • Study the application of the Intermediate Value Theorem in various functions
  • Learn about the epsilon-delta definition of continuity in depth
  • Explore examples of discontinuous functions, including the Dirichlet function
  • Practice solving limits involving piecewise functions
USEFUL FOR

Students and educators in calculus, mathematicians focusing on real analysis, and anyone seeking to deepen their understanding of limits and continuity in mathematical functions.

vbplaya
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I'm having a little trouble trying to figure out these problems. Any help would be appreciated.

g(x) = (x^2 - a^2)/(x-a) when x≠a but 8 when x=a... how do i find the constant a so that the function will be continuous on the entire real line?


f(x)= x^3 - x^2 + x - 2 on closed interval [0,3] f(c)=4. How do I find the value of c that is guaranteed by the Intermediate Value Theorem?
---I've proven via IVT that there exists a 0 in [0,3] but I do not know how to find the c value.


if f(x)=g(x) for x≠c and f(c)≠g(c) then either f or g is not continuous at c. True or False.
--- I haven't a clue. I can't even think of an example where f(x)=g(x) but f(c)≠g(c).


this last one I just want to make sure I'm doing it right.
Show that the Dirichlet function f(x)= 0 if x is rational and 1 if x is irrational
is not continuous at any real number.

if I just write D(x) = lim m→∞ lim n→∞ cos^2n (m! pi x) is that showing that the function is not continuous at any real number?

Again, I'd appreciate any help or pointers in the right direction. Thanks.
 
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cant u simplify the first one such that you get g(x) = x+a and a cna be any real number?

ALso for the continuity proof
use the DEFINITION OF CONTINUITY that is
[tex]\lim_{x \rightarrow c} f(x) = f(c)[/tex] if [tex]\forall \epsilon >0, \exists \delta>0[/tex] such that if [tex]0<|x-c|< \delta[/tex] then [tex]|f(x)-f(c)| <\epsilon[/tex]

you have to use the definition to prove continuity. Who says that that formula u wrote is continuous or not?
 

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