Comparing Electrostatic Potentials of Positive and Negative Charges

Click For Summary

Homework Help Overview

The discussion revolves around the electrostatic potentials associated with positive and negative test charges in the vicinity of a charge +Q. Participants are exploring the definitions and implications of electrostatic potential and potential energy in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question whether the electrostatic potential is greater for positive charges compared to negative charges, or if they are equal due to their magnitudes being the same. There is also a discussion about the terminology used to describe electrostatic potential versus potential energy.

Discussion Status

Some participants have provided clarifications regarding the definitions of electrostatic potential and potential energy, noting that while the potential energy differs based on the sign of the charge, the electrostatic potential remains the same for both positive and negative test charges. There is an ongoing exploration of these concepts without a clear consensus.

Contextual Notes

Participants are considering the assumption that the test charges are infinitesimal, which affects the discussion of their contributions to the electrostatic potential.

Tony11235
Messages
254
Reaction score
0
This is more of a general question and not a homework question, just to make it clear. Say two test charges are brought separately, one after the other, into the vicinity of a charge +Q. First test charge +q is brought to point B a distance r from +Q. This charge is removed and a test charge -q is brought to the same point. Now do we say that the electrostatic potential of +q is greater because it has a positive sign compared to -q? Or do we say their potentials are the equal because their magnetudes are the same? I assume it's the latter, isn't it?
 
Physics news on Phys.org
The electrostatic potential of the system is always
[tex] \phi(\vec{r}) = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r}[/tex]
assuming the test charges are truly infinitesimal (i.e. we neglect their contribution).

The electrostatic potential energy (or just energy) is
[tex] E_{q}= \frac{1}{4 \pi \epsilon_0} \frac{qQ}{r}[/tex]
in the case of a positive test charge and
[tex] E_{-q}= -\frac{1}{4 \pi \epsilon_0} \frac{qQ}{r}[/tex]
in the case of a negative test charge. The energy or electrostatic potential energy is different in each case, but the electrostatic potential of the charge Q is the same in both cases. It's mostly a matter of terminology.
 
Physics Monkey said:
The electrostatic potential of the system is always
[tex] \phi(\vec{r}) = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r}[/tex]
assuming the test charges are truly infinitesimal (i.e. we neglect their contribution).

The electrostatic potential energy (or just energy) is
[tex] E_{q}= \frac{1}{4 \pi \epsilon_0} \frac{qQ}{r}[/tex]
in the case of a positive test charge and
[tex] E_{-q}= -\frac{1}{4 \pi \epsilon_0} \frac{qQ}{r}[/tex]
in the case of a negative test charge. The energy or electrostatic potential energy is different in each case, but the electrostatic potential of the charge Q is the same in both cases. It's mostly a matter of terminology.

So to clear this up, the electrostatic potential energy of the positive test charge is greater?
 
Yes. It has positive energy while the negative charge has negative energy.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K
Replies
9
Views
2K
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
1K
Replies
2
Views
1K